javascript - 如何在 javascript 中对嵌套的对象数组进行排序？

Question

我有一个对象数组:

entities: [
  {
    name: "zBroomsticks PTY",
    id: 34098365,
    entityType: "personal",
    facilities: [
      {
        type: "Home loan",
        account: "032654 987465",
        existing: true,
        modified: "04/12/2018",
        limit: 100000
      },
      {
        type: "Credt card",
        account: "032654 987465",
        existing: false,
        modified: "04/12/2018",
        limit: 200000
      },
      {
        type: "Credt card",
        account: "032654 987465",
        existing: false,
        modified: "04/12/2018",
        limit: 10000
      },
      {
        type: "Credt card",
        account: "032654 987465",
        existing: false,
        modified: "04/12/2018",
        limit: 10000
      }
    ]
  },
  {
    name: "Mr John Doe -3409865, Mrs Jane Doe -34098365",
    id: 34098365,
    entityType: "business",
    facilities: [
      {
        type: "Overdraft",
        account: "032654 987465",
        existing: false,
        modified: "04/12/2018" ,
        limit: 10000
      }
    ]
  },
  {
    name: "Mr Jack",
    id: 34098365,
    entityType: "mixed",
    facilities: [
      {
        type: "Overdraft",
        account: "032654 987465",
        existing: false,
        modified: "04/12/2018",
        limit: 10000
      }
    ]
  }
]

我想按特定顺序对其进行排序:

1. entity.name:按字母升序排列。

2. entity.entityType: 1.个人 2.企业 3.混合

3. entity.facilities.limit:降序

这是我目前得到的代码:

sortData(entities) {
    var order = {
      entityType: { personal: 2, business: 1 }
    };

    return entities.map(ent =>
      entities.sort(
        (a, b) =>
          a.name - b.name ||
          order.entityType[a.facilities.entityType] - order.entityType[b.facilities.entityType]
      )
    );
}

我知道如何执行名称排序但找不到 2 和 3 的方法？

Link to code

Answer 1

首先，要按 names 排序，您可以使用 localeCompare() .其次，facilities 数组中没有属性 entityType 但您正在尝试访问它。现在，一种解决方案是首先使用 Array.map()获取一个新数组，其中 facilities 数组按 limit 属性排序，然后您可以先对 map() 返回的新数组进行排序通过 names 然后通过 entityType 属性，如下所示:

const input = [{name:"zBroomsticks PTY",id:34098365,entityType:"personal",facilities:[{type:"Home loan",account:"032654 987465",existing:true,modified:"04/12/2018",limit:100000},{type:"Credt card",account:"032654 987465",existing:false,modified:"04/12/2018",limit:200000},{type:"Credt card",account:"032654 987465",existing:false,modified:"04/12/2018",limit:10000},{type:"Credt card",account:"032654 987465",existing:false,modified:"04/12/2018",limit:10000}]},{name:"Mr John Doe -3409865, Mrs Jane Doe -34098365",id:34098365,entityType:"business",facilities:[{type:"Overdraft",account:"032654 987465",existing:false,modified:"04/12/2018",limit:10000}]},{name:"Mr Jack",id:34098365,entityType:"mixed",facilities:[{type:"Overdraft",account:"032654 987465",existing:false,modified:"04/12/2018",limit:10000}]},{name:"Mr Jack",id:34098365,entityType:"personal",facilities:[{type:"Overdraft",account:"032654 987465",existing:false,modified:"04/12/2018",limit:10000}]}];

let order = {
  entityType: {personal:1, business:2, mixed:3}
};

function sortData(entities)
{    
    let limitOrder = entities.map(e =>
    {
        e.facilities.sort((a, b) => b.limit - a.limit);
        return e;
    });

    return limitOrder.sort((a, b) =>
    {
        return a.name.localeCompare(b.name) ||
               order.entityType[a.entityType] - order.entityType[b.entityType];
    });
}

console.log(sortData(input));

.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}

请注意，我使用不同的 entityType 复制了与 name: "Mr Jack" 相关的对象，因此您可以看到当有两个对象时算法的执行情况等于 names。