java - Spring Boot - Jpa 独特且可分页

Question

我有一个使用 kotlin 的 Spring Boot v 2.1.8.RELEASE 项目。 我们使用 postgres 数据库，我有以下 JPA 查询

    @Query(value = " SELECT distinct grievance " +
               " FROM Grievance grievance" +
               " WHERE (grievance.auditProgramPortal=:auditProgramPortal AND grievance.owner.id=:organizationId) " +
               " OR (grievance.status=:status AND grievance.auditProgramPortal=:auditProgramPortal)" +
               " OR (grievance.auditProgramPortal=:auditProgramPortal AND grievance.owner.id=:organizationId)" +
               " OR (grievance.auditProgramPortal=:auditProgramPortal AND grievance.publicSubmission=:publicSubmission)")
fun findAnalystBodyGrievances(
        auditProgramPortal: Boolean,
        organizationId: Long,
        status: GrievanceStatus,
        publicSubmission: Boolean,
        pageable: Pageable): Page<Grievance>

当我按原样运行时 - 它工作正常。当我对行业字段进行排序时(请参阅下面的对象)- 我收到以下错误

org.postgresql.util.PSQLException: ERROR: for SELECT DISTINCT, ORDER BY expressions must appear in select list

相关对象摘录如下

申诉

@Entity
@Audited
@Table(name = "grievance")
class Grievance {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id")
    var id: Long? = null

    @Column(name = "title", nullable = false)
    var title: String? = null

    @Column(name = "description", columnDefinition = "text")
    var description: String? = null

    @Column(name = "public_description", columnDefinition = "text")
    var publicDescription: String? = null

    @Column(name = "related_to_identified_risk")
    var relatedToIdentifiedRisk: Boolean? = null


    @OneToOne
    @JoinColumn(name = "industry_id")
    var industry: Industry? = null
  }

行业

@Entity
@Table(name = "industry")
class Industry {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id")
    var id: Long? = null

    @Column(name = "name", nullable = false, unique = true)
    var name: String? = null

    @Column(name = "color", nullable = false, unique = false)
    var color: String? = null
}

我的问题是 - 修复查询以便仍返回页面的最简单方法是什么 如果我更新我的代码以使用以下查询 - 返回一个通用对象

@Query(value = " SELECT distinct grievance, grievance.industry " +
               " FROM Grievance grievance" +
               " WHERE (grievance.auditProgramPortal=:auditProgramPortal AND grievance.owner.id=:organizationId) " +
               " OR (grievance.status=:status AND grievance.auditProgramPortal=:auditProgramPortal)" +
               " OR (grievance.auditProgramPortal=:auditProgramPortal AND grievance.owner.id=:organizationId)" +
               " OR (grievance.auditProgramPortal=:auditProgramPortal AND grievance.publicSubmission=:publicSubmission)")

非常感谢对此的任何帮助

Answer 1

试试下面

@Query(value =" Select grievance from (SELECT distinct grievance, grievance.industry " +
" FROM Grievance grievance" +
" WHERE (grievance.auditProgramPortal=:auditProgramPortal AND grievance.owner.id=:organizationId) " +
" OR (grievance.status=:status AND grievance.auditProgramPortal=:auditProgramPortal)" +
" OR (grievance.auditProgramPortal=:auditProgramPortal AND grievance.owner.id=:organizationId)" +
" OR (grievance.auditProgramPortal=:auditProgramPortal AND grievance.publicSubmission=:publicSubmission))")