在我的采访中，我有一个问题如何实现序列化，我给出的答案是
public class SerializationSample {
public static void main(String args[]) {
...........
FileOutputStream fos = new FileOutputStream(outFile);
ObjectOutputStream oos = new ObjectOutputStream(fos);
oos.writeObject(serializableObject);
............
}
class SerializationBox implements Serializable {
............
............
}
但是面试官说，这会序列化整个对象，他问了两个问题
- 如果我想序列化单个对象，您将如何编写代码？
- 为什么我们在序列化过程中使用 long_integer id？
请任何人帮助我找到这个问题的答案
让我引用来自similar and already answered question的精华
The serialVersionUID represents your class version, and you should increment it if the current version of your class is not backwards compatible with its previous version.
和
automatically-generated UID is generated based on a class name, implemented interfaces, and all public and protected members. Changing any of these in any way will change the serialVersionUID. So you don't need to mess with them only if you are certain that no more than one version of the class will ever be serialized (either across processes or retrieved from storage at a later time).
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希望对您有所帮助。