java - 包含Thread.sleep的JUnit测试方法

Question

我有一个正在测试的模拟电梯的系统。我正在测试电梯是否到达特定楼层。这是我的测试代码:

    int chosenFloor=r.nextInt(6)+6;
    lc.moveLift(0, chosenFloor); //moving lift 0 to the chosen floor
    open=false;
    floor=chosenFloor;
    moving=false;

    assertEquals(floor, lc.getLifts()[0].getFloor());

现在 moveLift 方法调用这段代码:

    lift.setMoving(true);

    int fromFloor = lift.getFloor();
    setLiftFloor(fromFloor);
    lift.setMoving(true);

    if (toFloor > fromFloor) {

        for (int i = fromFloor; i < toFloor; i++) {
            animateUp(i);
            lift.setFloor(i);
        }

    } else {

        for (int i = fromFloor; i > toFloor; i--) {
            animateDown(i);
            lift.setFloor(i);
        }

    }

animateUp 调用这个方法:

    int lower = currentFloor * animationStepsPerFloor;
    int upper = lower + animationStepsPerFloor - 1;

    for (int i = 0; i < animationStepsPerFloor; i++) {
        try {
        Thread.sleep(50);
            } catch (Exception e) {
        e.printStackTrace();
            }
        lower++;
        upper++;}

如您所见，时间起着重要的作用。现在，根据我目前的测试，电梯不会移动。很明显我必须等待电梯移动，我怎么能在测试用例中做到这一点。我曾尝试将 Thread.sleep 放在我的测试用例中，但它是徒劳的。

Answer 1

It is obvious that I have to wait for the lift to move, how can I do it in a test case. I have tried placing Thread.sleep in my test case, but it's futile.

通常，当我对具有细微时序竞争条件的事物进行单元测试时，我在整个方法上使用 timeout，然后我有一个自旋循环等待条件发生。

@Test(timeout = 10000)
public void testSomeTimingIssue() throws Exception {
    while (!elevatorMoved) {
       // test elevator
       Thread.sleep(50);
    }
}