java - 使用 vlcj 示例运行示例 RTSP (JAVA)

Question

我尝试将来自 RTSP 服务器的视频流打开到 JAVA 应用程序中。首先我尝试运行这个例子:

package uk.co.caprica.vlcj.test.streaming;

import uk.co.caprica.vlcj.player.MediaPlayerFactory;
import uk.co.caprica.vlcj.player.headless.HeadlessMediaPlayer;
import uk.co.caprica.vlcj.test.VlcjTest;

/**
 * An example of how to stream a media file using RTSP.
 * <p>
 * The client specifies an MRL of <code>rtsp://@127.0.0.1:5555/demo</code>
 */
public class StreamRtsp extends VlcjTest {

  public static void main(String[] args) throws Exception {
    if(args.length != 1) {
      System.out.println("Specify a single MRL to stream");
      System.exit(1);
    }

    String media = args[0];
    String options = formatRtspStream("127.0.0.1", 5555, "demo");

    System.out.println("Streaming '" + media + "' to '" + options + "'");

    MediaPlayerFactory mediaPlayerFactory = new MediaPlayerFactory(args);
    HeadlessMediaPlayer mediaPlayer = mediaPlayerFactory.newHeadlessMediaPlayer();
    mediaPlayer.playMedia(media,
      options,
      ":no-sout-rtp-sap", 
      ":no-sout-standard-sap", 
      ":sout-all", 
      ":sout-keep"
    );

    // Don't exit
    Thread.currentThread().join();
  }

  private static String formatRtspStream(String serverAddress, int serverPort, String id) {
    StringBuilder sb = new StringBuilder(60);
    sb.append(":sout=#rtp{sdp=rtsp://@");
    sb.append(serverAddress);
    sb.append(':');
    sb.append(serverPort);
    sb.append('/');
    sb.append(id);
    sb.append("}");
    return sb.toString();
  }
}

但我总是得到相同的结果: 指定要流式传输的单个 MRL

http://i.stack.imgur.com/8iX0O.png

即使我删除了这部分:

if(args.length != 1) {
          System.out.println("Specify a single MRL to stream");
          System.exit(1);
        }

你能帮帮我吗？

Answer 1

听起来你实际上并没有将参数传递给程序，它期望从这一行传递参数:

String media = args[0];

如果您不想传递参数，只需将其更改为:

String media = "(location of rtsp to stream)";

...并删除上面已有的 if 语句。