java - 从服务器接收数据时出现 NoSuchElementFoundException

Question

public class cli
{
    public static void main(String args[]) throws IOException
    {
        int no,rec;
        Scanner sc = new Scanner(System.in);
        Socket s = new Socket("127.0.0.1", 1400);
        Scanner sc1 = new Scanner(s.getInputStream());

        System.out.println("Enter any number");
        no = sc.nextInt();
        PrintStream ps = new PrintStream(s.getOutputStream());
        ps.println(no);

        rec = sc1.nextInt();
        System.out.println("Receive number is " + rec);
    }
}

我正在向服务器发送一个数字并得到一个数字，该数字是发送数字的倍数，但我面临的问题是:rec=sc1.nextInt() 语句给了我 NoSuchElementFoundException。我究竟做错了什么？谢谢。

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服务器代码:

public class Server {
 public static void main(String args[]) throws IOException {
  ServerSocket ss = new ServerSocket(1400);
  System.out.println("Waiting ");
  Socket s1 = ss.accept();
  Scanner sc = new Scanner(s1.getInputStream());
  int a = sc.nextInt();
  int temp = 2 * a;
  PrintWriter ps = new PrintWriter(s1.getOutputStream());
  ps.write(temp);
  ps.flush();
  System.out.println("Got and sent Sucessfull " + temp);
  ss.close();
 }
}

Answer 1

问题是您没有向服务器的输出写入一个数字，而是一个带有 2*a 代码的字符。

int temp = 2 * a;
PrintWriter ps = new PrintWriter(s1.getOutputStream());
ps.write(temp);

这里调用write(temp)将带有 temp 代码的字符写入输出。例如，如果 a 为 16，则 temp 为 32，因此将其写入 PrintWriter 实际上写入了一个空格字符。如果您想将数字写成字符串，请执行以下操作:

ps.write(Integer.toString(temp));