Java 棋盘格，奇数/偶数 % 2 面板

Question

我已经成功地使用彩色面板将棋盘放在一起，但前提是用户要为行和列输入奇数。否则，当输入偶数时，它只会显示交替的彩色列。我正在努力弄清楚如何编写一个短段，通过使用 %2=0 检查它是奇数还是偶数，结果甚至改变了颜色。下面是我的代码。谢谢，请放轻松，我是编程新手! :-)

此外，我还创建了一个单独的 ColorPanel 类来构建彩色面板，然后将其拉入我的主程序。我没有费心把代码放在下面。

import javax.swing.*;
import java.awt.*;

public class Checkerboard extends JPanel{

public static void main(String[] args) {
    JFrame chBoard = new JFrame();
    chBoard.setTitle("Checkerboard");
    chBoard.setSize(800,800);
    chBoard.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

    String inputStr = JOptionPane.showInputDialog("Number of rows", "5");
    if (inputStr == null) return;
    int row = Integer.parseInt(inputStr);

    inputStr = JOptionPane.showInputDialog("Number of columns", "5");
    if (inputStr == null) return;
    int col = Integer.parseInt(inputStr);

    Container pane = chBoard.getContentPane();
    pane.setLayout(new GridLayout(row, col));

    Color BoxColor = Color.red;

    for ( int counter = 1;  counter <= row * col;  counter++ )
      {
        if (BoxColor == Color.red)
             BoxColor = Color.black;
        else
             BoxColor = Color.red;

        ColorPanel panel = new ColorPanel(BoxColor);
        pane.add(panel);
      }

    chBoard.setVisible(true);
}
}

Answer 1

将循环更改为:

for ( int x = 0;  x < row;  x++ ) {
    for(int y = 0; y < col; y++) {
        if((x + y)%2 == 0) {
            BoxColor = Color.red;
        } else {
            BoxColor = Color.black;
        }

        ...

    }
}