我的问题是对称解密。不是非对称解密。所以正确答案在这里 Decrypt PGP encrypted file with passphrase only in Java
我使用 gpg 来加密“hello”:
[root@shc-sma-cd13 opt]# echo "hello" | gpg --symmetric --armor --cipher-algo AES256 --passphrase "2R79P7z5f8350VEp" --batch
-----BEGIN PGP MESSAGE-----
Version: GnuPG v2.0.22 (GNU/Linux)
jA0ECQMC1XpaSrXhBAfU0jsBXw817k4k4iT++AGV8MUev4/gKkuIwAW2VaJsEANa
+0ZuqZgFp/8N7AndRhyNj5WGcloQQkLkwvIV3Q==
=GwQi
-----END PGP MESSAGE-----
我用Java解密字符串:
public class AESUtils1 {
private static final String KEY_VAL = "2R79P7z5f8350VEp";
public static String AESDecode(String content) {
try {
SecretKey key = new SecretKeySpec(KEY_VAL.getBytes(), "AES");
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.DECRYPT_MODE, key);
byte[] byte_content = new BASE64Decoder().decodeBuffer(content);
byte[] byte_decode = cipher.doFinal(byte_content);
String AES_decode = new String(byte_decode, "utf-8");
return AES_decode;
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (NoSuchPaddingException e) {
e.printStackTrace();
} catch (InvalidKeyException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (IllegalBlockSizeException e) {
e.printStackTrace();
} catch (BadPaddingException e) {
e.printStackTrace();
}
//如果有错就返加nulll
return null;
}
public static void main(String[] args) {
String encryptString = "jA0ECQMC1XpaSrXhBAfU0jsBXw817k4k4iT++AGV8MUev4/gKkuIwAW2VaJsEANa\n" +
" +0ZuqZgFp/8N7AndRhyNj5WGcloQQkLkwvIV3Q==\n" +
" =GwQi";
String decryptString = AESDecode(encryptString);
System.out.println("decryptString: " + decryptString);
}
但失败并显示错误消息:
javax.crypto.IllegalBlockSizeException: Input length must be multiple of 16 when decrypting with padded cipher
at com.sun.crypto.provider.CipherCore.doFinal(CipherCore.java:936)
at com.sun.crypto.provider.CipherCore.doFinal(CipherCore.java:847)
at com.sun.crypto.provider.AESCipher.engineDoFinal(AESCipher.java:446)
at javax.crypto.Cipher.doFinal(Cipher.java:2164)
at com.hpe.itsma.itsmaInstaller.AESUtils1.AESDecode(AESUtils1.java:33)
at com.hpe.itsma.itsmaInstaller.AESUtils1.main(AESUtils1.java:57)
decryptString: null
我很好奇我可以将它放入 Java 中的 gpg 的真正加密字符串是什么。 gpg 的输出与使用 Java 加密“hello”不同。
另一件有趣的事情是,每次我运行命令 echo "hello"| gpg --symmetric --armor --cipher-algo AES256 --passphrase "2R79P7z5f8350VEp"--batch
,结果总是不同的。是否可以解密由 gpg 加密的字符串。还是我用错了gpg?
最佳答案
谢谢大家。最后,我想出了解决方案。因为我的数据是对称加密的。解密将不同于非对称解密。我把我的代码放在下面,你也可以在这里找到相同的答案 Decrypt PGP encrypted file with passphrase only in Java
import org.bouncycastle.jce.provider.BouncyCastleProvider;
import org.bouncycastle.openpgp.*;
import org.bouncycastle.openpgp.operator.jcajce.JcaPGPDigestCalculatorProviderBuilder;
import org.bouncycastle.openpgp.operator.jcajce.JcePBEDataDecryptorFactoryBuilder;
import org.bouncycastle.util.io.Streams;
import java.io.*;
import java.security.NoSuchProviderException;
import java.security.Security;
public class SymmetricDecyption {
public static byte[] decrypt(byte[] var0, char[] var1) throws IOException, PGPException, NoSuchProviderException {
ByteArrayInputStream var2 = new ByteArrayInputStream(var0);
InputStream var11 = PGPUtil.getDecoderStream(var2);
PGPObjectFactory var3 = new PGPObjectFactory(var11);
Object var5 = var3.nextObject();
PGPEncryptedDataList var4;
if (var5 instanceof PGPEncryptedDataList) {
var4 = (PGPEncryptedDataList) var5;
} else {
var4 = (PGPEncryptedDataList) var3.nextObject();
}
PGPPBEEncryptedData var6 = (PGPPBEEncryptedData) var4.get(0);
InputStream var7 = var6.getDataStream((new JcePBEDataDecryptorFactoryBuilder((new JcaPGPDigestCalculatorProviderBuilder()).setProvider("BC").build())).setProvider("BC").build(var1));
PGPObjectFactory var8 = new PGPObjectFactory(var7);
PGPCompressedData var9 = (PGPCompressedData) var8.nextObject();
var8 = new PGPObjectFactory(var9.getDataStream());
PGPLiteralData var10 = (PGPLiteralData) var8.nextObject();
return Streams.readAll(var10.getInputStream());
}
public static void main(String[] var0) throws Exception {
String password = "2R79P7z5f8350VEp";
File file = new File("C:\\Users\\zhongtao.CORPDOM\\Desktop\\file.txt.asc");
InputStream input = new FileInputStream(file);
byte[] byt = new byte[input.available()];
input.read(byt);
Security.addProvider(new BouncyCastleProvider());
byte[] var5 = decrypt(byt, password.toCharArray());
System.out.println("Decrypted data is: " + new String(var5));
}
}
关于java - 如何使用 Java 解密字符串被 gpg 加密的字符串?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53739611/