我创建了一个程序，该程序采用从 0 开始并添加 Math.random()(0 到 0.999 之间的两倍)n 次创建的随机数组，并计算特定半径内每个位置的加权平均值。我目前有一个程序可以执行此操作，但我想知道如何使用环面创建一个程序。基本原则是最后一个元素现在等于第一个元素，当第一个元素更新其位置时，它会考虑其他元素之间的差异，包括数组中的一些最后元素。
如有任何帮助，我们将不胜感激。它对编码没有帮助，但根据其背后的原理，我无法弄清楚多次迭代如何做到这一点。
这是目前为止适用于一次迭代的代码。在一个之后，代码不正确并计算出错误的值。
import java.text.DecimalFormat;
import java.util.Scanner;
/**
* Created by jameshales on 12/03/2014.
*/
public class Torus {
public static void main(String[] args) {
DecimalFormat df = new DecimalFormat("#.###"); // this sets all decimals to a max of 3 decimal places.
System.out.println("how many numbers of agents on the real line?"); // This asks the question "how many numbers on the real line?" to the user.
Scanner input = new Scanner(System.in);
int n = 0;
n=Integer.parseInt(input.nextLine()); // the scanner reads the input and assigns it to the variable n
double[] agentPosition = new double[n]; // create an array with decimal places allowed called agentPosition
double[] newAgentPosition = new double[n]; // create an array with decimal places allowed called newAgentPosition
double[] originalAgentPosition = new double[n]; // create an array with decimal places allowed called originalAgentPosition
System.out.println("Please select your desired radius? select 1 normally"); // This asks the question "Please select your desired radius?
double r = 0;
r = input.nextDouble(); // the scanner reads the next input and assigns it to the variable r
int t = 0; // sets t to 0
double epsilon = 0.001; // this allows us to sets epsilon to 0.
// start the array from position 0 with its value set to 0
for (int i = 0; i <= n - 1; i++) { // starting from position 1 it creates a random number between 0 and 0.999 and adds it to the previous agentPosition to fill the array in a random increasing way.
if (i > 0)
agentPosition[i] = agentPosition[i - 1] + Math.random(); // this equation creates the random array
else agentPosition[i] =0.0;
}
System.arraycopy(agentPosition,0,originalAgentPosition,0,n);
// This takes the first randomly created array(agentPosition), copyies each element starting from 0 to n and calls it originalAgentPosition.
while(true) { // This is the start of the while loop, this will keep running until false
for (int i = 0; i <= n - 1; i++) {
// this will go through the array 1 position at a time in an increasing order from position 0 to n-1
double total1 = agentPosition[i]; // sets the initial value of total1 to 0
double total2 = 0; // sets the initial value of total2 to 0
int numposition = 1; // this starts at 1 so it includes the position in the array when dividing.(also stops dividing by 1)
for (int j = i - 1; j >= 0; j--) { // this will work from the initial value of the array to the one before the one selected.
if ((agentPosition[i] - agentPosition[j]) <= r) { // this calculates the absolute value of the difference between 2 positions on the array. (from i working downwards)
numposition++; // this sums the number of positions within the radius of the chosen position.
total1 += agentPosition[j]; // this sums up all the values within the radius below to the total1.
} else break; // stops the program once it has passed a position of a distance of 1
}
for (int k = i + 1; k <= n - 1 ; k++) { // this will go from the one after the position selected to the last position in the array to test if the distance is greater than 1, stops otherwise..
if (Math.abs(agentPosition[k] - agentPosition[i]) <= r) { // this calculates the absolute value of the difference between 2 positions on the array(i and positions greater).
numposition++; // this sums the number of positions within the radius of the chosen position.
total2 += agentPosition[k]; // this sums up all the values within the radius above to the total1.
} else break; // stops the program once it has passed a position of a distance of 1
}
for (int j = n - 2; j >= 1; j--) { // this will work from the initial value of the array to the one before the one selected.
if (((agentPosition[n-1] + agentPosition[i]) - agentPosition[j]) <= r) { // this calculates the absolute value of the difference between 2 positions on the array. (from i working downwards)
numposition++;
total1 += (agentPosition[j] - agentPosition[n - 1]); // this sums up all the values within the radius below to the total1.
} else break;// stops the program once it has passed a position of a distance of 1
}
for (int k = 1; k <= n - 2 ; k++) { // this will go from the one after the position selected to the last position in the array to test if the distance is greater than 1, stops otherwise..
if (Math.abs((agentPosition[i] - agentPosition[n - 1]) - agentPosition[k]) <= r) { // this calculates the absolute value of the difference between 2 positions on the array(i and positions greater).
numposition++; // this sums the number of positions within the radius of the chosen position.
total2 += (agentPosition[n - 1] + agentPosition[k]); // this sums up all the values within the radius above to the total1.
} else break;// stops the program once it has passed a position of a distance of 1
}
newAgentPosition[i] = (total1 + total2) / numposition; // this calculates the new weighted average. ( sum of assigned random variable/ sum of position)
}
for (int i = 0; i <= n - 1; i++){
if (newAgentPosition[i] > originalAgentPosition[n - 1]){
newAgentPosition[i] = newAgentPosition[i] - originalAgentPosition[n - 1];
}
if(newAgentPosition[i] < 0) { // This checks if the agentPosition is smaller than 0 and then adds the largest agent to make all the elements within the range.
newAgentPosition[i] = newAgentPosition[i] + originalAgentPosition[n - 1];
}
}
t++; // This sums up how many iterations it will take.
double largestDiff = 0.0; // This assigns largestDiff to 0
for (int i = 0; i <= n-1; i++) {
double diff = Math.abs(agentPosition[i] - newAgentPosition[i]); // This calculates the difference between the previous and current array at position i.
if(diff > largestDiff) // If the difference between the agents is bigger than 0, assign it to the variable largestDiff.
largestDiff = diff;
}
if(largestDiff <= epsilon){ // This checks if the difference is bigger than the set epsilon,
break; // This stops the program if the difference is smaller than epsilon
}
agentPosition = new double[n];
System.arraycopy(newAgentPosition, 0, agentPosition, 0, n); // This takes the newly generated array(newAgentPosition), copyies each element starting from 0 to n and assigns it back to agentPosition. (this stops the problem j and with taking the newly created elements.)
}
for (int i = 0 ; i <= n - 1; i++) { // starting from position 1 it creates a random number between 0 and 0.999 and adds it to the previous agentPosition to fill the array in a random increasing way.
System.out.println(i + ": " + df.format(originalAgentPosition[i]) + "\t->\t" + df.format(agentPosition[i]));
}
int sumdofclusters = 1; // This sets the sum of clusters to 1
System.out.println("The different clusters are:\n" + df.format(agentPosition[0])); // This prints out the first cluster only.
for (int i = 1; i <= n - 1 ; i++) {
if(Math.abs(agentPosition[i] - agentPosition[i - 1]) >= epsilon) { // This checks if the element after the element at hand is different by a set epsilon.(how to work out different clusters)
sumdofclusters++; // This sums the number of clusters.
System.out.println(df.format(agentPosition[i])); // This prints out the different clusters other than the first 1.
}
}
System.out.println("Number of clusters is:" + sumdofclusters); // This prints out the number of clusters.
System.out.println("Number of iterations:" + t); // This prints out the number of iterations.
}
}
最佳答案
您可以使用带模除法的数组创建循环列表。
getElementAt(double[] arr, int index)
{
index = index % arr.length;
index = index + arr.length; // If index is negative, modulus division gives us negative result, so this makes it positive.
index = index % arr.length; // In case the previous step made index >= n
return arr[index]
}
如果n是arr.length然后
0 <= index < n会像往常一样。
n <= index将环绕列表(例如 arr[n] == arr[0] 、 arr[n+1] == arr[1] 等)
index < 0将在另一个方向环绕列表(例如 arr[-1] == arr[n-1] 、 arr[-2] == arr[n-2] 等)
关于java - 创建一个像环面一样工作的数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/22411553/