我有一个复杂的 JSON，如下所示，我需要对其进行递归解析。递归的最终结果是 Map> type of object，其中 key 是 audience-name value，内部 map 是 Text-key，Title-value。 这只是完整 JSON 的一部分。
"sections": {
"1": {
"1": {
"1": {
"title": "xxx",
"text": "xxx",
"tags": {
"audience": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
},
"styleHint": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
}
}
},
"title": "xxx",
"text": "xxx",
"tags": {
"audience": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
},
"styleHint": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
}
}
},
"2": {
"title": "xxx",
"text": "xxx",
"tags": {
"audience": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
},
"styleHint": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
}
}
},
"title": "xxx",
"text": "xxx",
"tags": {
"audience": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
},
"2": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
},
"styleHint": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
}
}
},
"2": {
"title": "xxx",
"text": "xxx",
"tags": {
"audience": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
},
"styleHint": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
}
},
"anchor":"xxx"
},
"3": {
"1": {
"title": "xxx",
"text": "xxx",
"tags": {
"audience": {
"tag": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
},
"styleHint": {
"tag": {
"name": "xxx",
"title": "xxx",
"id": "xxx"
}
}
}
},
"title": "xxx",
"text": "xxx",
"tags": {
"audience": {
"1": {
"name": "xxx",
"title": "xxx",
"id": "xxxx"
}
},
"styleHint": {
"1": {
"name": "xx",
"title": "xxx",
"id": "xxxx"
}
}
}
}
}
我为此使用 JSONObject 只是为了很晚才意识到迭代以相反的顺序发生:(
我试图递归地解析整个结构并将其反转以对我有利。但是订单正在失控 :( :( 主要是因为文本、标题、片段跟在第二个文本、标题之后并且有 2 个听众姓名。该部分的文本和标题被跳过，导致整个订单受到影响
请帮忙!!我目前的实现如下
private Map<String, Map<String, String>> parseTextAndTitle(JSONObject json,
Map<String, Map<String, String>> ttMap, String article,
List<String> usrGrp) throws JSONException {
logger.info("Entering method..");
String userGroup = null;
Map<String, String> titleAndText = new LinkedHashMap<String, String>();
Map<String, String> currMap = new LinkedHashMap<String, String>();
Map<String, String> tempMap = new LinkedHashMap<String, String>();
Iterator<String> keys = json.sortedKeys();
while (keys.hasNext()) {
String key = keys.next();
JSONObject value = null;String firstKey = null;
String text = null;String title = null;
int length = 0;
try {
value = json.getJSONObject(key);
if (key.equalsIgnoreCase(STYLEHINT) || key.equalsIgnoreCase(ANCHOR)
|| key.equalsIgnoreCase(INLINE)) {
continue;
}
if (key.equals(TEXT)) {
text = json.getString(key);
text = removeHtmlTag(text);
logger.debug("TEXT RETRIEVED:" + text);
if(text != null) {
titleAndText.put(text, "");
}
else
logger.debug("Text not retrieved!!");
}
if (key.equals(TITLE)) {
title = json.getString(TITLE);
title = appendNewline(title);
logger.debug("TITLE RETRIEVED:" + title);
if (title != null) {
for (Map.Entry<String, String> iter : titleAndText
.entrySet())
firstKey = iter.getKey();
if(firstKey != null) {
titleAndText.put(firstKey, title);
}
else
logger.debug("NO key present in textAndTitle Map!!");
}
}
if (key.equals(AUDIENCE_TAG)) {
try {
length = value.length();
for (int i = 0; i < length; i++) {
userGroup = (String) value.getJSONObject(
String.valueOf(i + 1)).get(NAME);
logger.debug("USERGROUP RETRIEVED:" + userGroup);
usrGrp.add(userGroup);
}
} catch (Exception e) {
userGroup = (String) value.getJSONObject(TAG).get(NAME);
logger.debug("USERGROUP RETRIEVED:" + userGroup);
usrGrp.add(userGroup);
}
}
else{
parseTextAndTitle(value, ttMap, article, usrGrp);
}
} catch (Exception e) {
logger.debug("value not a JSON Object..rather an element");
// Extract the text values
if (key.equals(TEXT)) {
text = json.getString(key);
text = removeHtmlTag(text);
logger.debug("TEXT RETRIEVED:" + text);
if(text != null) {
titleAndText.put(text, "");
}
else
logger.debug("Text not retrieved!!");
}
if (key.equals(TITLE)) {
title = json.getString(TITLE);
title = appendNewline(title);
logger.debug("TITLE RETRIEVED:" + title);
if (title != null) {
for (Map.Entry<String, String> iter : titleAndText
.entrySet())
firstKey = iter.getKey();
if(firstKey != null) {
titleAndText.put(firstKey, title);
}
else
logger.debug("NO key present in textAndTitle Map!!");
}
}
}
if (!(usrGrp.isEmpty()) && !(titleAndText.isEmpty())
&& title != null) {
if(usrGrp.size() > 1)
{
for(int i=0;i<usrGrp.size();i++)
{
//If user group already present, extract current text,title map
//If not put usergroup as key, text,title map as value
if (ttMap.containsKey(usrGrp.get(i))) {
currMap = ttMap.get(usrGrp.get(i));
if (currMap.isEmpty()) {
ttMap.put(usrGrp.get(i), titleAndText);
} else {
currMap = ttMap.get(usrGrp.get(i));
for (Map.Entry<String, String> entry : currMap
.entrySet()) {
tempMap.put(entry.getKey(),
(String) entry.getValue());
}
for (Map.Entry<String, String> ttEntry : titleAndText
.entrySet()) {
tempMap.put(ttEntry.getKey(),
(String) ttEntry.getValue());
}
ttMap.put(usrGrp.get(i),tempMap);
// titleAndText = new LinkedHashMap<String, String>();
tempMap = new LinkedHashMap<String, String>();
}
}
else {
ttMap.put(usrGrp.get(i), titleAndText);
}
}
titleAndText.clear();
}
else
{
if (ttMap.isEmpty())
{
tempMap = titleAndText;
ttMap.put(usrGrp.get(0), tempMap);
}
else {
currMap = ttMap.get(usrGrp.get(0));
if (currMap.isEmpty()) {
ttMap.put(usrGrp.get(0), titleAndText);
}else {
currMap = ttMap.get(usrGrp.get(0));
for (Map.Entry<String, String> entry : currMap
.entrySet()) {
tempMap.put(entry.getKey(),
(String) entry.getValue());
}
for (Map.Entry<String, String> ttEntry : titleAndText
.entrySet()) {
tempMap.put(ttEntry.getKey(),
(String) ttEntry.getValue());
}
ttMap.put(usrGrp.get(0),tempMap);
titleAndText.clear();
}
}
}
usrGrp.clear();
}
}
logger.info("Exiting method..");
return ttMap;
}
最佳答案
修改@sklimkovitch 代码以使其在一些复杂的 Json 结构中工作...
public void loopThroughJson(Object input) throws JSONException {
if (input instanceof JSONObject) {
Iterator<?> keys = ((JSONObject) input).keys();
while (keys.hasNext()) {
String key = (String) keys.next();
if (!(((JSONObject) input).get(key) instanceof JSONArray))
if (((JSONObject) input).get(key) instanceof JSONObject) {
loopThroughJson(((JSONObject) input).get(key));
} else
System.out.println(key + "=" + ((JSONObject) input).get(key));
else
loopThroughJson(new JSONArray(((JSONObject) input).get(key).toString()));
}
}
if (input instanceof JSONArray) {
for (int i = 0; i < ((JSONArray) input).length(); i++) {
JSONObject a = ((JSONArray) input).getJSONObject(i);
loopThroughJson(a);
}
}
}
关于java - 通过 JSONObject 递归解析 JSON 以针对特定键获取值，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/21354546/