我有一个JTable
,它显示了该类型的数据数组
String [] data = {"String1", "String2", "String3", "String4"};
但在 JTable 中,我只显示前 3 项,第四项对用户隐藏。但即使在 JTable 中未显示的 String4
的基础上,我也会对表进行排序。我阅读了 JTable 教程,我发现了如何使用 TableRowSorter
并设置一个 Comparator
但是方法 setComparator
希望将要排序的列作为其参数,但这我不可用。
谁能帮我解决这个任务?谢谢你
最佳答案
诀窍是,将列包含在 TableModel
中,但将其从 TableColumnModel
中移除
“A”列实际上是随机生成的,所以它会以不可预知的方式排序
您可以使用类似 sorter.setSortable(1, false);
的方式禁止列进行排序,这可用于防止用户单击列标题并破坏您的“隐藏”排序.
import java.awt.BorderLayout;
import java.awt.EventQueue;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import java.util.Comparator;
import java.util.List;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.JScrollPane;
import javax.swing.JTable;
import javax.swing.RowSorter;
import javax.swing.SortOrder;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
import javax.swing.table.AbstractTableModel;
import javax.swing.table.TableRowSorter;
public class MagicSort {
public static void main(String[] args) {
new MagicSort();
}
public MagicSort() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
ex.printStackTrace();
}
JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.add(new TestPane());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
public class TestPane extends JPanel {
private SortOrder order = SortOrder.ASCENDING;
public TestPane() {
RowDataTableModel model = new RowDataTableModel();
TableRowSorter<RowDataTableModel> sorter = new TableRowSorter<>(model);
sorter.setComparator(0, new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
return o1.compareTo(o2);
}
});
JTable table = new JTable(model);
table.setRowSorter(sorter);
table.getColumnModel().removeColumn(table.getColumn("A"));
setLayout(new BorderLayout());
add(new JScrollPane(table));
JButton change = new JButton("Change");
add(change, BorderLayout.SOUTH);
change.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
sort(sorter);
}
});
sort(sorter);
}
protected void sort(TableRowSorter<RowDataTableModel> sorter) {
List<RowSorter.SortKey> keys = new ArrayList<>(1);
keys.add(new RowSorter.SortKey(0, order));
sorter.setSortKeys(keys);
switch (order) {
case ASCENDING:
order = SortOrder.DESCENDING;
break;
case DESCENDING:
order = SortOrder.UNSORTED;
break;
case UNSORTED:
order = SortOrder.ASCENDING;
break;
}
}
}
public class RowDataTableModel extends AbstractTableModel {
private List<RowData> data = new ArrayList<>(25);
public RowDataTableModel() {
for (int index = 0; index < 10; index++) {
data.add(new RowData(index));
}
}
public String getKeyColumnValue(int row) {
return data.get(row).get(0);
}
@Override
public int getRowCount() {
return data.size();
}
@Override
public int getColumnCount() {
return 5;
}
@Override
public Object getValueAt(int rowIndex, int columnIndex) {
return data.get(rowIndex).get(columnIndex);
}
}
public class RowData {
private List<String> values = new ArrayList<>();
public RowData(int offset) {
offset *= 5;
for (int index = 1; index < 5; index++) {
values.add(Character.toString((char) ('A' + (offset + index))));
}
values.add(0, Character.toString((char) ('A' + Math.random() * 26)));
}
public String get(int col) {
return values.get(col);
}
}
}
注意:但是,从视觉上看,这可能会让用户感到困惑,所以我会谨慎使用它。
关于java - 按 JTable 中未包含的值对 JTable 进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32863249/