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将关联数组作为参数传递给函数以避免重复迭代大量关联数组的最佳方法是什么？这样我就可以为函数提供我选择的任何数组来打印。这是我所拥有的:
# Snippet
declare -A weapons=(
['Straight Sword']=75
['Tainted Dagger']=54
['Imperial Sword']=90
['Edged Shuriken']=25
)
print_weapons() {
for i in "${!weapons[@]}"; do
printf "%s\t%d\n" "$i" "${weapons[$i]}"
done
}
print_weapons
最佳答案
可以引用local -n
declare -A weapons=(
['Straight Sword']=75
['Tainted Dagger']=54
['Imperial Sword']=90
['Edged Shuriken']=25
)
print_weapons() {
local -n array=$1
for i in "${!array[@]}"; do
printf "%s\t%d\n" "$i" "${array[$i]}"
done
}
print_weapons weapons
关于linux - 将关联数组作为 Bash 的参数传递，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/17557434/