我想使用这个 webflux 客户端代码来发送有回复和无回复的 POST 请求。我试过这个代码实现:
public class RestClientBuilder {
private String token;
private String username;
private String password;
private URL gatewayUrl;
private SslContextBuilder sslContextBuilder;
public static RestClientBuilder builder() {
return new RestClientBuilder();
}
public RestClientBuilder token(String token) {
this.token = validateAndTrim(token, "Token");
return this;
}
public RestClientBuilder usernamePassword(String username, String password) {
this.username = validateAndTrim(username, "Username");
this.password = validateAndTrim(password, "Password");
return this;
}
private String validateAndTrim(String value, final String parameter) {
if (value == null || value.trim().isEmpty()) {
throw new IllegalArgumentException(parameter + " is empty");
}
return value.trim();
}
public RestClientBuilder gatewayUrl(String gatewayUrl) {
String urlSt = validateAndTrim(gatewayUrl, "Gateway URL");
try {
this.gatewayUrl = new URL(urlSt);
} catch (MalformedURLException e) {
throw new IllegalArgumentException("Malformed URL: " + urlSt, e);
}
return this;
}
public RestClientBuilder truststore(File truststoreFile) {
getSslContextBuilder().trustManager(truststoreFile);
return this;
}
public RestClientBuilder sslCertificate(File keyCertChainFile, File keyFile, String keyPassword) {
getSslContextBuilder().keyManager(keyCertChainFile, keyFile, keyPassword);
return this;
}
public RestClient build() throws SSLException {
SslContext sslContext = sslContextBuilder != null ? sslContextBuilder.build() : null;
return new RestClient(gatewayUrl.toString(), token, username, password, sslContext);
}
private SslContextBuilder getSslContextBuilder() {
if (sslContextBuilder == null) {
sslContextBuilder = SslContextBuilder.forClient();
}
return sslContextBuilder;
}
}
其余客户端的实现:
public class RestClient {
private WebClient client;
private String gatewayUrl;
public RestClient(String gatewayUrl, String token, String username, String password, SslContext sslContext) {
this.gatewayUrl = gatewayUrl;
WebClient.Builder builder = WebClient.builder().baseUrl(gatewayUrl);
if (sslContext != null) {
HttpClient httpClient = HttpClient.create().secure(sslContextSpec -> sslContextSpec.sslContext(sslContext));
ClientHttpConnector httpConnector = new ReactorClientHttpConnector(httpClient);
builder.clientConnector(httpConnector);
}
if (username != null && password != null) {
builder.filter(basicAuthentication(username, password));
}
client = builder.build();
}
public Mono<Void> executeOnly(ReportRequest transaction) {
Mono<ReportRequest> transactionMono = Mono.just(transaction);
return client.post().uri(gatewayUrl)
.accept(MediaType.APPLICATION_XML)
.contentType(MediaType.APPLICATION_XML)
.body(transactionMono, ReportRequest.class)
.retrieve()
.bodyToMono(Void.class);
}
}
进行远程调用:
public class ReportingProcessor {
private String URL2 = "......";
public void collectEnvironmentData() throws JAXBException {
ReportRequest report = new ReportRequest();
report.setVersion("1.0");
RestClient client = null;
try {
client = RestClientBuilder.builder()
.gatewayUrl(URL2)
// .token(contract.getTerminal_token())
// .usernamePassword("user", "password")
// .truststore(new File("server.pem"))
// .sslCertificate(new File("client.pem"), new File("clientKey.p8"), "secret")
.build();
} catch (SSLException e) {
e.printStackTrace();
}
Mono<Void> result = client.executeOnly(report);
Void response = result.block();
}
当我删除 Void response = result.block();
时,请求不会发送。我找不到原因。你能给我一些建议,告诉我如何在不使用 block()
的情况下使客户端代码正常工作吗?
最佳答案
无论何时使用 Spring-webflux,您都必须牢记一件事。即你不必打破你的链条。因为有必要,有人应该在你的链上调用订阅。因为它适用于 RXJava 规范。
如果你打破了链,那么你必须调用block()
,这不是推荐的。
您必须按照以下方式修改您的代码。
假设您有一个处理程序正在调用您的 collectEnvironmentData()
方法,而您的方法正在调用远程服务。
public Mono<ServerResponse> handelerMethod(ServerRequest request){
return collectEnvironmentData().flatMap(aVoid -> ServerResponse.ok().build());
}
你的方法应该修改为
public Mono<Void> collectEnvironmentData() throws JAXBException {
ReportRequest report = new ReportRequest();
report.setVersion("1.0");
RestClient client = null;
try {
client = RestClientBuilder.builder()
.gatewayUrl(URL2)
// .token(contract.getTerminal_token())
// .usernamePassword("user", "password")
// .truststore(new File("server.pem"))
// .sslCertificate(new File("client.pem"), new File("clientKey.p8"),
//"secret").build();
} catch (SSLException e) {
e.printStackTrace();
}
return client.executeOnly(report);
}
以上述方式更改您的实现,希望它能起作用。
关于java - 请求不会在没有 block 的情况下发送(),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58364708/