在第4行
执行赋值语句时发生了什么,编译器是否忽略new运算符
并保持foo
变量为null或发生了其他事情来处理这个尴尬的时刻?
public class Foo {
// creating an instance before its constructor has been invoked, suppose the "initializing"
// gets printed in constructor as a result of the next line, of course it will not print it
private Foo foo = new Foo();//Line 4
public Foo() {
System.out.println("initializing");
}
}
最佳答案
编译器在这里没有做任何特别的事情。它可能会警告您这行不通,但这很难确定。
您将收到 StackOverflowError。
public class Foo {
private Foo foo = new Foo();//Line 4
public Foo() {
System.out.println("initializing");
}
public static void main(String... args) {
Foo foo = new Foo();
}
}
打印
Exception in thread "main" java.lang.StackOverflowError
at Foo.<init>(Foo.java:9)
at Foo.<init>(Foo.java:7)
at Foo.<init>(Foo.java:7)
.. many deleted ...
at Foo.<init>(Foo.java:7)
at Foo.<init>(Foo.java:7)
关于java - 在类本身中创建一个实例,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11191995/