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在 C++ 中,我知道创建多行字符串的最佳规范方法是创建相邻字符串并让编译器在编译时连接它们,如下所示:
string s = "This is a very long string ...\n"
" and it keeps on going...";
在 Java 中,我知道的唯一方法是连接:
String s = "This is a very long string ...\n" +
" and it keeps on going...";
问题是,这会在运行时生成单个字符串,还是 java 实际上也在编译时连接?问题出现的原因是由于以下行为:
String s1 = "abc";
String s2 = "abc";
System.out.println(s1 == s2); // this prints true, because the compiler
// generates only one "abc" object
String s3 = "a";
s3 += "bc";
System.out.println(s1 == s3); // false