我正在使用 spring-ws-2.3.1,在为 web 服务创建客户端时,有时我会遇到 SoapFaultClientException,如下所示,
<SOAP-ENV:Body>
<SOAP-ENV:Fault>
<faultcode>SOAP-ENV:Server</faultcode>
<faultstring>There was a problem with the server so the message could not proceed</faultstring>
<faultactor>InvalidAPI</faultactor>
<detail>
<ns0:serviceException xmlns:ns0="http://www.books.com/interface/v1">
<ns1:messageId xmlns:ns1="http://www.books.org/schema/common/v3_1">5411</ns1:messageId>
<ns1:text xmlns:ns1="http://www.books.org/schema/common/v3_1">Locale is invalid.</ns1:text>
</ns0:serviceException>
</detail>
</SOAP-ENV:Fault>
我正在尝试获取 ServiceException 的“messageId”和“Text”,但我不能。请在下面找到代码,
catch (SoapFaultClientException ex) {
SoapFaultDetail soapFaultDetail = ex.getSoapFault().getFaultDetail(); // <soapFaultDetail> node
// if there is no fault soapFaultDetail ...
if (soapFaultDetail == null) {
throw ex;
}
SoapFaultDetailElement detailElementChild = soapFaultDetail.getDetailEntries().next();
Source detailSource = detailElementChild.getSource();
Object detail = webServiceTemplate.getUnmarshaller().unmarshal(detailSource);
System.out.println("Detail"+detail.toString());//This object prints the jaxb element
}
“detail”对象返回 JaxbElement。有没有优雅的方法来解析 soap 错误。
如有任何帮助,我们将不胜感激。
最佳答案
最后,我可以解析 soap 错误异常了,
catch (SoapFaultClientException ex) {
SoapFaultDetail soapFaultDetail = ex.getSoapFault().getFaultDetail(); // <soapFaultDetail> node
// if there is no fault soapFaultDetail ...
if (soapFaultDetail == null) {
throw ex;
}
SoapFaultDetailElement detailElementChild = soapFaultDetail.getDetailEntries().next();
Source detailSource = detailElementChild.getSource();
Object detail = webServiceTemplate.getUnmarshaller().unmarshal(detailSource);
JAXBElement<serviceException> source = (JAXBElement<serviceException>)detail;
System.out.println("Text::"+source.getText()); //prints : Locale is invalid.
}
我没有找到任何其他优雅的方式,所以我希望这应该是解决方案。
关于java - spring-ws中如何解析SoapFaultClientException,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43329256/