所以我有一个双排按钮。单击按钮后,我需要能够获取它的索引以用于进一步编码(这是一个类似扫雷游戏的游戏)。到目前为止,这是我的代码。我有一个双 for 循环来为每个按钮创建一个 Handle 事件,但我不知道如何获取每个按钮的索引。我试过 e.getSource() 但它只返回无用的地址。我试过给每个按钮一个 Id 但它只接受字符串。我不知道下一步该怎么做。
import javafx.application.Application;
import javafx.application.Platform;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.geometry.Insets;
import javafx.geometry.Pos;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.layout.BorderPane;
import javafx.scene.layout.GridPane;
import javafx.scene.layout.HBox;
import javafx.scene.layout.VBox;
import javafx.scene.paint.Color;
import javafx.stage.Stage;
import java.awt.event.ActionListener;
import java.util.ArrayList;
import java.util.Random;
public class main extends Application {
Button[][] tiles = new Button[8][8];
Integer[][] mine_field = new Integer[8][8];
Stage window;
public void start(Stage primaryStage){
BorderPane Field = new BorderPane();
HBox Start_Show = new HBox(50);
Button Start = new Button("Start");
Button Show = new Button ("Show");
Start.setStyle("-fx-font-size: 15.5pt;");
Show.setStyle("-fx-font-size: 15.5pt;");
Start_Show.getChildren().addAll(Start, Show);
Start_Show.setAlignment(Pos.CENTER);
Start_Show.setPadding(new Insets(10,10,10,10));
Field.setTop(Start_Show);
tiles = create_tiles(tiles);
int i;
int j;
VBox columns = new VBox();
for(i=0; i<8; i++){
HBox row = new HBox();
for(j=0; j<8; j++){
row.getChildren().add(tiles[i][j]);
}
columns.getChildren().add(row);
}
columns.setAlignment(Pos.CENTER);
columns.setPadding(new Insets(0,0,0,100));
Field.setCenter(columns);
mine_field = set_mines(mine_field);
Start.setOnAction(new EventHandler<ActionEvent>() {
@Override
public void handle(ActionEvent event) {
start(primaryStage);
}
});
Show.setOnAction(new EventHandler<ActionEvent>() {
@Override
public void handle(ActionEvent e){
int i = 0;
int j = 0;
for(i=0; i<8; i++){
for(j=0; j<8; j++){
if(mine_field[i][j] == 1) {
tiles[i][j].setStyle("-fx-font-size: 15.5pt;");
tiles[i][j].setTextFill(Color.RED);
tiles[i][j].setMaxHeight(150);
tiles[i][j].setMaxWidth(251);
tiles[i][j].setText("M");
}
}
}
}
});
for(i=0; i<8; i++){
for(j=0; j<8; j++){
Tile_Handler tile_handle = new Tile_Handler();
tiles[i][j].setOnAction(tile_handle);
}
}
Scene scene = new Scene(Field, 600, 600);
primaryStage.setTitle("MineSweeper!");
primaryStage.setScene(scene);
primaryStage.show();
}
public Button[][] create_tiles(Button[][] array){
int i;
int j;
for(i=0; i<8; i++){
for(j=0; j<8; j++){
Button my_butt = new Button("?");
my_butt.setStyle("-fx-font-size: 20pt;");
my_butt.prefWidthProperty();
array[i][j] = my_butt;
}
}
return array;
}
public Integer[][] set_mines(Integer[][] array){
Random random = new Random();
int i;
int j;
int k;
for(i=0; i<8; i++){
for(j=0; j<8; j++){
array[i][j] = 0;
}
}
for(i=0; i<10; i++){
j = random.nextInt(8);
k = random.nextInt(8);
array[j][k] = 1;
}
return array;
}
class Tile_Handler implements EventHandler<ActionEvent> {
public void handle(ActionEvent e){
System.out.println("yo clicked one button located at ");
}
}
public static void main(String[] args){
Application.launch(args);
}
}
最佳答案
您可以使用实用函数和 lambda 表达式即时创建带有参数的图 block 处理程序:
private EventHandler<ActionEvent> createTileHandler(int x, int y) {
return event -> tileHandler(x, y);
}
private void tileHandler (int x, int y){
System.out.println(String.format("Clicked tile at (%d,%d)", x, y));
}
然后像这样应用到不同的按钮:
...
for (int i=0; i<8; i++){
for (int j=0; j<8; j++) {
tiles[i][j].setOnAction(createTileHandler(i, j));
}
}
...
或者,修改您当前的解决方案,您可以向 Tile_Handler
添加两个成员,因此在创建它时将其附加到特定坐标:
class Tile_Handler implements EventHandler<ActionEvent> {
private int x, y;
public Tile_Handler(int x, int y) {
this.x = x;
this.y = y;
}
public void handle(ActionEvent e){
System.out.println(String.format("yo clicked one button located at %d,%d",x,y));
}
}
然后把实例化改成
Tile_Handler tile_handle = new Tile_Handler(i, j);
关于java - 我怎样才能得到为我的程序点击的每个按钮的索引?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34189259/