我有这个 JSON 要反序列化:
{
"first-name": "Alpha",
"last-name": "Beta",
"gender": "m"
}
我想将它序列化为 2 种不同的格式:
[A]
{
"first-name": "Alpha",
"last-name": "Beta",
"gender": "m"
}
[B]
{
"firstName": "Alpha",
"lastName": "Beta",
"gender": "m"
}
我可以将其序列化为一种格式:仅 [A] 或仅 [B]。这是我将其序列化为 [B] 的代码:
public String firstName;
public String lastName;
public String gender;
@JsonProperty("firstName")
public String getFirstNameCC() {
return firstName;
}
@JsonProperty("first-name")
public void setFirstNameD(String firstName) {
this.firstName = firstName;
}
@JsonProperty("lastName")
public String getLastNameCC() {
return lastName;
}
@JsonProperty("last-name")
public void setLastNameD(String lastName) {
this.lastName = lastName;
}
public String getGender() {
return gender;
}
public void setGender(String gender) {
this.gender = gender;
}
我在此处阅读了有关 JsonView
的信息 http://www.baeldung.com/jackson-json-view-annotation (“5. 自定义 JSON View ”部分)但它仅更改其值。我想更改字段名称,如上例所示。任何人都可以对此发表见解吗?
最佳答案
我不确定我是否完全理解你的问题,但据我所知,你可以做这样的事情来实现不同的序列化。
创建一个自定义注释来保存所有可能的不同序列化选项:
@Target(ElementType.FIELD)
@Retention(RetentionPolicy.RUNTIME)
public @interface CustomJsonProperty {
String propertyName();
String format();
@Target(ElementType.FIELD)
@Retention(RetentionPolicy.RUNTIME)
@Documented
@interface List {
CustomJsonProperty[] value();
}
}
相应地注释你的类:
@JsonSerialize(using = CustomJsonPropertySerializer.class)
public class Bar {
@CustomJsonProperty.List({
@CustomJsonProperty(propertyName = "first-name", format = "A"),
@CustomJsonProperty(propertyName = "firstName", format = "B")
})
private String firstName;
@CustomJsonProperty.List({
@CustomJsonProperty(propertyName = "last-name", format = "A"),
@CustomJsonProperty(propertyName = "lastName", format = "B")
})
private String lastName;
@CustomJsonProperty.List({
@CustomJsonProperty(propertyName = "gender-x", format = "A"),
@CustomJsonProperty(propertyName = "gender", format = "B")
})
private String gender;
@JsonIgnore
private String format;
//getters & setters
}
创建自定义序列化程序来解释您的新注释:
public class CustomJsonPropertySerializer extends JsonSerializer<Bar> {
@Override
public void serialize(Bar bar, JsonGenerator jsonGenerator, SerializerProvider serializerProvider)
throws IOException {
jsonGenerator.writeStartObject();
Field[] fields = bar.getClass().getDeclaredFields();
for (Field field : fields) {
field.setAccessible(true);
Object value = null;
try {
value = field.get(bar);
} catch (IllegalAccessException e) {
e.printStackTrace();
}
if (field.isAnnotationPresent(CustomJsonProperty.List.class)) {
CustomJsonProperty[] properties = field.getAnnotation(CustomJsonProperty.List.class).value();
CustomJsonProperty chosenProperty = null;
for (CustomJsonProperty c : properties) {
if (c.format().equalsIgnoreCase(bar.getFormat())) {
chosenProperty = c;
break;
}
}
if (chosenProperty == null) {
//invalid format given, use first format then
chosenProperty = properties[0];
}
jsonGenerator.writeStringField(chosenProperty.propertyName(), value.toString());
}
}
jsonGenerator.writeEndObject();
}
}
现在您可以序列化您的对象,同时考虑属性名称的不同格式:
public static void main(String[] args) throws IOException {
Bar bar1 = new Bar("first", "last", "m", "A");
Bar bar2 = new Bar("first", "last", "m", "B");
ObjectMapper mapper = new ObjectMapper();
String json1 = mapper.writeValueAsString(bar1);
String json2 = mapper.writeValueAsString(bar2);
System.out.println(json1);
System.out.println(json2);
}
输出:
{"first-name":"first","last-name":"last","gender-x":"m"}
{"firstName":"first","lastName":"last","gender":"m"}
当然,上面的序列化程序只适用于 Bar 对象,但这可以通过在父类(super class)上使用 abstract String getFormat();
继承并更改自定义序列化程序以接受父类(super class)来轻松解决类型,而不是 Bar。
也许有比创建自己的东西更简单的方法,但我不知道。如果有什么地方不清楚,请告诉我,我可以再次详细说明。
关于java - Jackson 将字段序列化为不同的名称,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36646098/