我想用输入文件中的行填充数组列表,输入文件如下所示:
7f00000000000000000000000000000000000000000000000000000000000000027f00000000000000000000000000000000000000000000000000000000000000027f00000000000000000000000000000000000000000000000000000000000000020101
7f00000000000000000000000000000000000000000000000000000000000000037f00000000000000000000000000000000000000000000000000000000000000037f00000000000000000000000000000000000000000000000000000000000000030101
7f00000000000000000000000000000000000000000000000000000000000000047f00000000000000000000000000000000000000000000000000000000000000047f00000000000000000000000000000000000000000000000000000000000000040101
7f00000000000000000000000000000000000000000000000000000000000000057f00000000000000000000000000000000000000000000000000000000000000057f00000000000000000000000000000000000000000000000000000000000000050101
7f00000000000000000000000000000000000000000000000000000000000000067f00000000000000000000000000000000000000000000000000000000000000067f00000000000000000000000000000000000000000000000000000000000000060101
我想基于此创建的 Java 数据对象会将这些行中的每一行都作为一个新字符串,并且它们将一起存在于一个列表中,可以这么说*。
因此,在我尝试将文件的行读入此数组列表的不同部分时,我无法弄清楚我需要在主程序中的何处声明数组列表。我的计划是用单独的方法填充它:
import java.io.*;
import java.util.Scanner;
import java.util.List;
import java.util.Array;
import java.util.ArrayList;
class evmTest {
public static void main(String[] args) {
Array<String> inputLinesObject = new ArrayList<String>();
// populate from file
inputLinesObject = readFile("/Users/s.matthew.english/codes.txt", inputLinesObject);
System.out.println(Array.toString(inputLinesObject));
}
private static void readFile(String fileName, Array<String> inputLines) {
try {
File file = new File(fileName);
Scanner scanner = new Scanner(file);
while (scanner.hasNextLine()) {
// System.out.println(scanner.nextLine());
inputLines.add(scanner.nextLine());
}
scanner.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
}
return inputLines;
}
}
也许我可以先将它实例化为null
,然后将那个null
数组列表传递给要填充的方法?
* 最后一句话中的术语并不完全准确 - 请原谅我 - 我正在重新调整 Java 的词汇,但我认为我想做的事情应该足够清楚。如果不是,请告诉我,我很乐意澄清。
最佳答案
对于您的测试,您只需在 try 之上实例化 ArrayList
import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class EvmTest {
public static void main(final String[] args) {
// populate from file
final List<String> inputLinesObject = EvmTest.readFile("/Users/s.matthew.english/codes.txt");
for (final String line : inputLinesObject) {
System.out.println(line);
}
}
private static List<String> readFile(final String fileName) {
final List<String> inputLinesObject = new ArrayList<>();
try {
final File file = new File(fileName);
final Scanner scanner = new Scanner(file);
while (scanner.hasNextLine()) {
// System.out.println(scanner.nextLine());
inputLinesObject.add(scanner.nextLine());
}
scanner.close();
} catch (final FileNotFoundException e) {
e.printStackTrace();
}
return inputLinesObject;
}
}
这有两个优点: - 您不修改 readFile 方法的输入参数 - 您不必处理 List 为空或 null 的情况
关于java - 通过从扫描仪中读取行来实例化一个 ArrayList,在哪里声明对象?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46428880/