我有这门课:
public class StructUserType extends UserType {
MembersList membersList = new MembersList();
public List<Member> getMembers() {
return Collections.unmodifiableList(membersList.members);
}
static class MembersList {
List<Member> members = new ArrayList<>();
}
public static class Member implements Identifiable {
private Integer id;
public Integer getId() {
return id;
}
}
}
我有一个 List
对象:
List<SmbpUserType> userTypes = new ArrayList<>();
我想找到等于某个 id 的 Member
。我试过如下:
Integer id = 1;
userTypes.stream()
.filter(StructUserType.class::isInstance)
.map(StructUserType.class::cast)
.forEach(structUserType -> {
structUserType.getMembers()
.stream()
.filter(m -> m.getId() == id)
.findFirst().orElse(null);
});
我想,当内部流中的过滤器运行并找到第一个成员时,返回该成员包含的父元素,那些 UserType
。
经典风格的模拟:
for (UserType userType : userTypes) {
if (userType instanceof StructUserType) {
List<StructUserType.Member> members = ((StructUserType) userType).getMembers();
for (StructUserType.Member member : members) {
if (member.getId() == id) {
return userType;
}
}
}
}
return null;
最佳答案
用filter
替换forEach
,寻找满足内部流管道条件的StructUserType
实例。然后获取 Stream
的第一个元素(如果存在)。
return
userTypes.stream()
.filter(StructUserType.class::isInstance)
.map(StructUserType.class::cast)
.filter(st -> st.getMembers()
.stream()
.anyMatch(m -> m.getId().equals(id)))
.findFirst()
.orElse(null);
关于java - 从流中获取父对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48906718/