java - 如何检查List是否按顺序包含多个元素

Question

假设我有一个列表，

Arrays.asList("A","B","C","D");

Java 中是否有一种方便的方法允许我检查此列表以查看元素 C 和 D 是否按该顺序在此列表中？

类似的东西:

Collections.containsOrderedElements(list,"C","D");
Collections.containsOrderedElements(list,"A","B","C");

上面的方法会返回true但是

Collections.containsOrderedElements(list,"A","C");

不会吗？

感谢您的宝贵时间。

Answer 1

有一个方法可以提供帮助(Collections.indexOfSubList(sourceList,subList)):

List<String> list = Arrays.asList("A", "B", "C", "D");

System.out.println( (Collections.indexOfSubList(list, Arrays.asList("C", "D"))>= 0));
System.out.println( (Collections.indexOfSubList(list, Arrays.asList("A","B","C"))>= 0));
System.out.println( (Collections.indexOfSubList(list, Arrays.asList("A", "C"))>= 0));

它打印:

true
true
false