我使用的是 Python 2.7.3，我正在尝试将数据发布到我的本地 Web 服务器。我发布的数据是我的树莓派的温度读数。我知道 url 是正确的，因为如果我使用 postman chrome 插件，数据会成功发布并且我会收到一条返回消息。在 postman 中，我只能使用表单数据，而不是 x-www-form-urlencoded，这是我的 python 脚本设置内容类型的方式。我可以将其更改为表单数据吗？
Python 代码:
import os
import glob
import time
import threading
import urllib
import urllib2
os.system('modprobe w1-gpio')
os.system('modprobe w1-therm')
base_dir = '/sys/bus/w1/devices/'
device_folder = glob.glob(base_dir + '28*')[0]
device_file = device_folder + '/w1_slave'
def read_temp_raw():
f = open(device_file, 'r')
lines = f.readlines()
f.close()
return lines
def read_temp():
lines = read_temp_raw()
while lines[0].strip()[-3:] != 'YES':
time.sleep(0.2)
lines = read_temp_raw()
equals_pos = lines[1].find('t=')
if equals_pos != -1:
temp_string = lines[1][equals_pos+2:]
temp_c = float(temp_string) / 1000.0
temp_f = temp_c * 9.0 / 5.0 + 32.0
temperature = {'tempf':temp_f, 'tempc':temp_c}
return temperature
def post():
threading.Timer(1800.0, post).start()
temperature = read_temp()
data = temperature
data['room'] = 'Server Room'
print(data)
data=urllib.urlencode(data)
path='http://client.pathtophppage' #the url you want to POST to
req=urllib2.Request(path, data)
req.add_header("Content-type", "application/x-www-form-urlencoded")
page=urllib2.urlopen(req).read()
post()
错误:
pi@raspberrypi ~/Documents $ python Temperature.py
{'tempc': 22.0, 'tempf': 71.6, 'room': 'Server Room'}
Traceback (most recent call last):
File "Temperature.py", line 49, in <module>
post()
File "Temperature.py", line 45, in post
page=urllib2.urlopen(req).read()
File "/usr/lib/python2.7/urllib2.py", line 127, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 407, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 520, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 439, in error
result = self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 379, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 626, in http_error_302
return self.parent.open(new, timeout=req.timeout)
File "/usr/lib/python2.7/urllib2.py", line 407, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 520, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 445, in error
return self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 379, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 528, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 500: Internal Server Error
最佳答案
节省您的时间，使用这个 requests httpRequests 的库，
简单的应用
import requests
url = 'http://url.com'
query = {'field': value}
res = requests.post(url, data=query)
print(res.text)
关于python - 使用 Python 脚本将数据发布到 Web 服务器，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30459762/