我正在尝试将选择器作为参数通过 Slider
传递给对象嵌套函数。
我希望 istouchEnd
可以获取 .storage1
作为 Slider
的参数,但是 this.storage
从不从 Slider
函数接收参数。
有没有什么方法可以通过 Slider
函数将 span
标记作为参数传递(或获取任何内容)?
'use strict';
const blueMethods = {
count: 1,
istouchStart(e) {
this.coordX = e.touches[0].clientX;
return this.coordX;
},
istouchMove(e) {
let drag = e.touches[0].clientX;
let dist = Math.sqrt(drag + this.coordX);
},
istouchEnd(e) {
let dist = e.changedTouches[0].clientX - this.coordX;
$(this.storage).text(dist);
}
}
function Slider(target, storage) {
Slider.target = target;
Slider.storage = storage;
$(Slider.target).stop(true, true).on({
touchstart:blueMethods.istouchStart,
touchmove:blueMethods.istouchMove,
touchend:blueMethods.istouchEnd
});
};
const box1 = Slider('.page1', '.storage1');
box1;
* {
margin: 0;
padding: 0;
}
.box {
width: 100%;
height: 70%;
float: left;
}
.page1 {
width: 48vw;
height: 80vh;
background-color: lightblue;
float: left;
}
.page2 {
width: 48vw;
height: 80vh;
background-color: orange;
float: left;
}
<div class="box">
<div class="page1"></div>
<div class="page2"></div>
</div>
<div class="textbox">
<span class="storage1"></span>
<span class="storage2" data-count></span>
</div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
最佳答案
当您设置事件处理程序(它们是某个对象中的方法)并希望传递一些参数并为它们提供访问权 this
时,您可以通过以下方式创建处理程序 - 例如对于函数 istouchEnd
istouchEnd(storage) {
return (e) => {
let dist = e.changedTouches[0].clientX - this.coordX;
$(storage).text(dist);
}
}
如您所见,istouchEnd
不是处理程序,但它创建并返回处理程序(使用 arrow function ),它可以访问 this.coordX
和存储参数。您可以通过将 touchend:blueMethods.istouchEnd
更改为
touchend:blueMethods.istouchEnd(storage)
'use strict';
const blueMethods = {
count: 1,
istouchStart() {
return (e) => {
this.coordX = e.touches[0].clientX;
return this.coordX;
}
},
istouchMove() {
return (e) => {
let drag = e.touches[0].clientX;
let dist = Math.sqrt(drag + this.coordX);
}
},
istouchEnd(storage) {
return (e) => {
let dist = e.changedTouches[0].clientX - this.coordX;
$(storage).text(dist);
}
}
}
function Slider(target, storage) {
Slider.target = target;
Slider.storage = storage;
$(Slider.target).stop(true, true).on({
touchstart:blueMethods.istouchStart(),
touchmove:blueMethods.istouchMove(),
touchend:blueMethods.istouchEnd(storage)
});
};
const box1 = Slider('.page1', '.storage1');
box1;
* {
margin: 0;
padding: 0;
}
.box {
width: 100%;
height: 70%;
float: left;
}
.page1 {
width: 48vw;
height: 80vh;
background-color: lightblue;
float: left;
}
.page2 {
width: 48vw;
height: 80vh;
background-color: orange;
float: left;
}
<div class="box">
<div class="page1"></div>
<div class="page2"></div>
</div>
<div class="textbox">
<span class="storage1"></span>
<span class="storage2" data-count></span>
</div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
关于javascript - 我将如何通过嵌套函数将元素作为参数传递?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54976686/