我有以下来自 API 的数据结构。
$scope.cityList = [{
"_id": {
"$oid": "584ebd7f734d1d55b6dd4e5e"
},
"cityName": "New York",
"region": "north",
"people": [
{ "id": 1, "name": "x" },
{ "id": 2, "name": "y" },
{ "id": 3, "name": "z" },
{ "id": 4, "name": "a" },
{ "id": 5, "name": "b" },
{ "id": 6, "name": "c" }
]
},
{
"_id": {
"$oid": "584ebd7f734d1d55b6dd4e5e"
},
"cityName": "New Jersey",
"region": "South",
"people": [
{ "id": 1, "name": "x" },
{ "id": 2, "name": "y" },
{ "id": 3, "name": "z" },
{ "id": 4, "name": "a" },
{ "id": 5, "name": "b" },
{ "id": 6, "name": "c" }
]
}]
我正在尝试设置两个下拉菜单:
- 第一个显示
cityNames
的列表 - 第二个显示来自所选城市的所有人
姓名
的列表。
我还想将所选用户名的id
保存到一个变量中。
到目前为止我已经试过了:
<select ng-model="city">
<option ng-repeat="city in cityList" value="{{city.cityName}}">{{city.cityName}}</option>
</select>
<select ng-model="selectedItem">
<optgroup ng-repeat="option in cityList | filter: city">
<option ng-repeat="x in option.people">{{x}}</option>
</select>
最佳答案
你应该使用 ng-options
:
<select ng-model="selectedCity"
ng-options="c as c.cityName for c in cityList">
</select>
<select ng-model="selectedPerson"
ng-options="p as p.name for p in selectedCity.people">
</select>
关于javascript - 使用 AngularJS 使用对象数组填充和过滤下拉列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41117227/