我写了一些代码来解析html,但是结果不是我想要的:
import urllib2
html = urllib2.urlopen('http://dummy').read()
from BeautifulSoup import BeautifulSoup
soup = BeautifulSoup(html)
for definition in soup.findAll('span', {"class":'d'}):
definition = definition.renderContents()
print "<meaning>", definition
for exampleofuse in soup.find('span',{"class":'x'}):
print "<exampleofuse>", exampleofuse, "<exampleofuse>"
print "<meaning>"
有什么方法可以在类属性为“d”或“x”时获取字符串?
下面的html代码是我要解析的:
<span class="d">calculated by adding several amounts together</span>
<span class="x">an average rate</span>
<span class="x">at an average speed of 100 km/h</span>
<span class="d">typical or normal</span>
<span class="x">average intelligence</span>
<span class="x">20 pounds for dinner is average</span>
那么,这就是我想要的结果:
<definition>calculated by adding several amounts together
<example_of_use>an average rate</example_of_use>
<example_of_use>at an average speed of 100 km/h</example_of_use>
</definition>
<definition>typical or normal
<example_of_use>average intelligence</example_of_use>
<example_of_use>20 pounds for dinner is average</example_of_use>
</definition>
最佳答案
是的,您可以获得 html 中的所有跨度,然后为每个检查“d”或“x”类,如果有,则打印它们。
这样的东西可能有用(未经测试):
for span in soup.findAll('span'):
if span.find("span","d").string:
print "<definition>" + span.find("span","d").string + "</definition>"
elif span.find("span","x").string:
print "<example>" + span.find("span","x").string + "</example>"
关于python - 在 Python 中使用 BeautifulSoup 解析 html,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6396655/