linux - 使用 printf 如何转义 shell 脚本中的特殊字符？

Question

我正在尝试在 shell 中使用 printf 格式化字符串，我将从文件中获取输入字符串，该字符串具有特殊字符，如 %,',"",,\user,\tan 等

如何转义输入字符串中的特殊字符？

例如

#!/bin/bash
# 

string='';
function GET_LINES() {

   string+="The path to K:\Users\ca, this is good";
   string+="\n";
   string+="The second line";
   string+="\t";
   string+="123"
   string+="\n";
   string+="It also has to be 100% nice than %99";

   printf "$string";

}

GET_LINES;

我希望这会以我想要的格式打印

The path to K:\Users\ca, this is good
The second line   123
It also has to be 100% nice than %99

但它给出了意想不到的结果

./script: line 14: printf: missing unicode digit for \U
The path to K:\Users\ca, this is good
The second line 123
./script: line 14: printf: `%99': missing format character
It also has to be 100ice than 

那么我怎样才能在打印时去掉特殊字符呢？ echo -e 也有问题。

Answer 1

尝试

printf "%s\n" "$string"

参见 printf(1)