c++ - 字符串操作 C++

Question

我需要制作一些功能，但我不知道如何做。

1. 连接两个字符串，输入位置并输出字符串中该位置的字符

示例:s1=第一个，s2=第二个； s1+s2=第一第二，pos=3,7,10，输出=ren

这是我针对一个职位的代码，但我不知道如何制作多个职位，主要问题是如何限制职位的输入:

s=s1+s2;
cin>>pos;
cout<<s[pos-1];

在字符串中定义元音并用字符串替换该元音

示例:s=firstsecondthird、元音=i、str=EXA、输出=fEXArstsecondthEXArd

这就是我所知道的，我不知道如何用 string(str) 替换元音

cin>>vowel;
if(check is defined character vowel)
{
   cin>>str;
   .
   .
   .
}

谢谢

Answer 1

捕获! :)

#include <iostream>
#include <string>
#include <cstring>

int main() 
{
    std::cout << "Enter first string: ";

    std::string s1;
    std::cin >> s1;

    std::cout << "Enter second string: ";

    std::string s2;
    std::cin >> s2;

    s1 += s2;

    std::cout << "The joined string is " << s1 << std::endl;

    std::cout << "Enter several positions in the joined string (0-stop): ";

    std::string s3;
    std::string::size_type pos;

    while ( std::cin >> pos && pos != 0 )
    {
        if ( --pos < s1.size() ) s3 += s1[pos];
    }

    std::cout << "You have selected the following letters " << s3 << std::endl;

    const char *vowels = "aeiou";
    char c;

    do
    {
        c = '\0';
        std::cout << "Enter a vowel: ";
    } while ( std::cin >> c && !std::strchr( vowels, c ) );

    if ( c != '\0' )
    {
        for ( auto pos = s1.find( c, 0 ); 
              pos != std::string::npos; 
              pos = s1.find( c, pos ) )
        {
            const char *t = "EXA";
            const size_t n = 3;

            s1.replace( pos, 1, t );
            pos += n;
        }

        std::cout << "Now the joined string looks like " << s1 << std::endl;
    }       

    return 0;
}

如果输入

first
second
3 7 10 0
i

那么程序输出将是

Enter first string: first
Enter second string: second
The joined string is firstsecond
Enter several positions in the joined string (0-stop): 3 7 10 0
You have selected the following letters ren
Enter a vowel: i
Now the joined string looks like fEXArstsecond

您可以将其用作您出色的程序的模板。:)