有人可以向我解释一下为什么会在这里崩溃吗?
#include <memory>
#include <functional>
struct Teacher : std::enable_shared_from_this<Teacher> {
struct Timetable;
std::shared_ptr<Timetable> timetable;
Teacher (int n) : timetable(std::make_shared<Timetable>(*this, n)) {}
};
struct Period {
std::shared_ptr<Teacher> teacher;
Period (const std::shared_ptr<Teacher>& t) : teacher(t) {}
};
struct Teacher::Timetable {
Teacher& teacher;
std::shared_ptr<Period> homeForm;
Timetable (Teacher& t, int n) : teacher(t), // Assume something is done with n.
homeForm( std::make_shared<Period>(teacher.shared_from_this()) ) {} // Crashes.
// homeForm( std::make_shared<Period>(std::shared_ptr<Teacher>(&teacher)) ) {} // Also crashes.
};
int main() {
std::shared_ptr<Teacher> teacher = std::make_shared<Teacher>(3);
}
不是 teacher.shared_from_this()
自std::shared_ptr<Teacher> teacher
起允许在这里已经是shared_ptr了吗?如果没有,我该如何初始化homeForm
正确吗?
最佳答案
问题是您的代码调用 shared_from_this
之前std::shared_ptr<Teacher>
已全面建成。从某种程度上来说,Teacher
是有道理的。子对象必须在智能指针完全构造之前构造。
如果你像这样改变代码,
struct Teacher : std::enable_shared_from_this<Teacher> {
struct Timetable;
std::shared_ptr<Timetable> timetable;
Teacher() {}
void init(int n) { this->timetable = std::make_shared<Timetable>(*this, n); }
};
// Everything else unchanged
int main() {
std::shared_ptr<Teacher> teacher = std::make_shared<Teacher>();
teacher->init(3);
}
它会运行良好。
请注意,我不建议将此作为重构。构造函数应尽可能完全初始化对象。看看你的代码,在我看来,你可能想考虑更激进地重新构建它。您真的需要所有这些交叉引用共享指针吗?
关于c++ - 因shared_ptr而崩溃,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35832798/