C++ 如何格式化包含可变整数的文本行，使其在给定宽度内右对齐？

Question

格式化目标如下

   Absolute value of the number you entered : 723
                 Square root of that number : 26.89
       Rounding this to the nearest integer : 27
  Two random numbers between 27 and 723 are : ...

这是我的代码

  cout << right << setw(50) << "Absolute value of the number you entered : " << absoluteValue << endl;
  cout << right << setw(50) << "Square root of that number : " << squareRoot << endl;
  cout << right << setw(50) << "Rounding this to the nearest integer : " << roundedSquareRoot << endl;
  cout << right << setw(50) << "Two random numbers between " << roundedSquareRoot << " and " << absoluteValue << " are : ";

当我运行时我得到这个

   Absolute value of the number you entered : 723
                 Square root of that number : 26.89
       Rounding this to the nearest integer : 27
                   Two random numbers between 27 and 723 are :

最下面一行右对齐和 setw() 仅适用于第一个“文本” 我如何使它适用于该行上的所有内容？ 谢谢

编辑:明确地说，我只想让底线像前三条线一样。

Answer 1

您需要将最后一行呈现为单个字符串。
最好的选择是预先构建该字符串。

std::sstream  lastLineStream;
lastLineStream << "Two random numbers between " 
               << roundedSquareRoot << " and " 
               << absoluteValue << " are : ";

现在您可以将其打印为单个字符串。

 cout << right << setw(50) << "Rounding this to the nearest integer : " << roundedSquareRoot << endl;
 cout << right << setw(50) << lastLineStream.str();

注意:

优先选择'\n' 而不是std::endl。 它们都做同样的事情，然后 std::endl 将刷新缓冲区。手动刷新缓冲区通常是错误的做法。