所以,我正在制作一个单词过滤器,用星号替换坏单词,但是如果使用像 ąężźć 等特殊字符,则可能有很多可能的单词组合。
如何让 boost::ireplace_all 将它们视为基本字符 aezzc?
所以
boost::ireplace_all("żąć", "a", "*");
和 boost::ireplace_all("zac", "a", "*");
会分别产生ż*ć
和z*c
吗?
编辑/扩展示例:
const std::set<std::string> badwords =
{
"<not nice word>",
"<another not nice word>"
};
void FilterBadWords(std::string& s)
{
for (auto &badword : badwords)
boost::ireplace_all(s, badword, "*");
}
int main()
{
std::string a("hello you <not nice word> person");
std::string b("hęlló you <nót Nićę wórd> person");
FilterBadWords(a);
FilterBadWords(b);
//a equals "hello you * person"
//b equals "hęlló you * person"
//or as many * as the replaced string lenght, both are fine
}
最佳答案
Boost Locale 通过 ICU 支持主排序规则:
事实证明,让它发挥作用非常棘手。基本上,与 char
字符串,因为 Boost 字符串算法对代码点一无所知,只是逐字节迭代(和比较)输入序列(嗯, char
by char
,但那就是这里有点困惑)。
因此,解决方案在于转换为 utf32 字符串(这可以通过使用 std::wstring
的 GCC 实现,因为 wchar_t
是 32 位的)。 Utf16 通常也应该“工作”,但它仍然存在我刚才概述的遍历问题,只是更加罕见。
现在,我创建了一个快速而简单的自定义 Finder 谓词:
template <typename CharT>
struct is_primcoll_equal
{
is_primcoll_equal(const std::locale& Loc=std::locale()) :
m_Loc(Loc), comp(Loc, boost::locale::collator_base::primary) {}
template< typename T1, typename T2 >
bool operator()(const T1& Arg1, const T2& Arg2) const {
// TODO use `do_compare` methods on the collation itself that
// don't construct basic_string<> instances
return 0 == comp(std::basic_string<CharT>(1, Arg1), std::basic_string<CharT>(1, Arg2));
}
private:
std::locale m_Loc;
boost::locale::comparator<CharT> comp;
};
它效率极低,因为它每次调用都会构造单字符字符串。这是因为do_compare
方法不是 collator<>
的公共(public) API 的一部分。我留下一个自定义collator<>
并将其用作读者的练习。
接下来,我们模仿 replace_all
接口(interface)通过包装 find_format_all
相反:
template<typename SequenceT, typename Range1T, typename Range2T>
inline void collate_replace_all(
SequenceT& Input,
const Range1T& Search,
const Range2T& Format,
const std::locale& Loc=std::locale() )
{
::boost::algorithm::find_format_all(
Input,
::boost::algorithm::first_finder(Search, is_primcoll_equal<typename SequenceT::value_type>(Loc)),
::boost::algorithm::const_formatter(Format) );
}
现在我们只需要字符串加宽转换就可以了:
void FilterBadWords(std::string& s) {
using namespace boost::locale::conv;
std::wstring widened = utf_to_utf<wchar_t>(s, stop);
for (auto& badword : badwords) {
detail::collate_replace_all(widened, badword, L"*"/*, loc*/);
}
s = utf_to_utf<char>(widened, stop);
}
完整程序
#include <boost/algorithm/string/replace.hpp>
#include <boost/locale.hpp>
#include <iostream>
#include <locale>
#include <set>
#include <string>
const std::set<std::string> badwords =
{
"<not nice word>",
"<another not nice word>"
};
namespace detail {
template <typename CharT>
struct is_primcoll_equal
{
is_primcoll_equal(const std::locale& Loc=std::locale()) :
m_Loc(Loc), comp(Loc, boost::locale::collator_base::primary) {}
template< typename T1, typename T2 >
bool operator()(const T1& Arg1, const T2& Arg2) const {
// assert(0 == comp(L"<not nice word>", L"<nót Nićę wórd>"));
// TODO use `do_compare` methods on the collation itself that
// don't construct basic_string<> instances
return 0 == comp(std::basic_string<CharT>(1, Arg1), std::basic_string<CharT>(1, Arg2));
}
private:
std::locale m_Loc;
boost::locale::comparator<CharT> comp;
};
template<typename SequenceT, typename Range1T, typename Range2T>
inline void collate_replace_all(
SequenceT& Input,
const Range1T& Search,
const Range2T& Format,
const std::locale& Loc=std::locale() )
{
::boost::algorithm::find_format_all(
Input,
::boost::algorithm::first_finder(Search, is_primcoll_equal<typename SequenceT::value_type>(Loc)),
::boost::algorithm::const_formatter(Format) );
}
}
void FilterBadWords(std::string& s) {
using namespace boost::locale::conv;
std::wstring widened = utf_to_utf<wchar_t>(s, stop);
for (auto& badword : badwords) {
detail::collate_replace_all(widened, badword, L"*"/*, loc*/);
}
s = utf_to_utf<char>(widened, stop);
}
static_assert(sizeof(wchar_t) == sizeof(uint32_t), "Required for robustness (surrogate pairs, anyone?)");
int main()
{
auto loc = boost::locale::generator().generate("");
std::locale::global(loc);
std::string a("hello you <not nice word> person");
std::string b("hęlló you <nót Nićę wórd> person");
FilterBadWords(a);
FilterBadWords(b);
std::cout << a << "\n";
std::cout << b << "\n";
}
输出
在我的系统上:
hello you * person
hęlló you * person
1 显然,Coliru 执行环境中的区域设置支持不完整
关于c++ - boost::ireplace 是否可以像基本字符一样对待特殊字符? (例如 'ź' 为 'z' ),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27883220/