我正在与您分享我在使用可变函数参数的类中遇到的一个问题。它是下面代码中显示的类 Thread。它是 std::thread 的包装器,以便使用函数模式。
我想对这个函数使用多态性,将类 Thread 继承到一个新类 Functor 中,但是 gcc 返回以下错误:
#include <thread>
#include <iostream>
using namespace std;
template<class... Args>
class Thread
{
public:
virtual void operator()(Args...) = 0;
void run(Args... args)
{
std::thread t(std::forward< Thread<Args...> >(*this), std::forward<Args>(args)...);
t.join();
}
};
template<class... Args>
class Functor : public Thread<Args...>
{
public:
// generates the errors bellow
virtual void operator()(Args... /*args*/)
{
}
// doesnot work since the pure virtual function wants another prototype of function.
// void operator()(int)
// {
// }
};
int main()
{
int a = 12;
Functor<int> f;
f.run(ref(a));
return 0;
}
from t-Thread-args2.cpp:1: /usr/lib/gcc/x86_64-unknown-linux-gnu/4.7.2/../../../../include/c++/4.7.2/tuple: In instantiation of ‘struct std::_Head_base, false>’: /usr/lib/gcc/x86_64-unknown-linux-gnu/4.7.2/../../../../include/c++/4.7.2/tuple:215:12: required from ‘struct std::_Tuple_impl, int>’ /usr/lib/gcc/x86_64-unknown-linux-gnu/4.7.2/../../../../include/c++/4.7.2/tuple:507:11: required from ‘class std::tuple, int>’ /usr/lib/gcc/x86_64-unknown-linux-gnu/4.7.2/../../../../include/c++/4.7.2/functional:1601:39: required from ‘struct std::_Bind_simple(int)>’ /usr/lib/gcc/x86_64-unknown-linux-gnu/4.7.2/../../../../include/c++/4.7.2/thread:133:9: required from ‘std::thread::thread(_Callable&&, _Args&& ...) [with _Callable = Thread; _Args = {int}]’ t-Thread-args2.cpp:14:83: required from ‘void Thread::run(Args ...) [with Args = {int}]’ t-Thread-args2.cpp:42:17: required from here /usr/lib/gcc/x86_64-unknown-linux-gnu/4.7.2/../../../../include/c++/4.7.2/tuple:166:13: error: cannot declare field ‘std::_Head_base, false>::_M_head_impl’ to be of abstract type ‘Thread’ t-Thread-args2.cpp:7:7: note: because the following virtual functions are pure within ‘Thread’: t-Thread-args2.cpp:10:18: note: void Thread::operator()(Args ...) [with Args = {int}]
我不太明白这个错误,因为纯虚函数在派生类中定义得很好。但是,在将函数 run() 移动到派生类 (Functor) 时,它起作用了。
提前致谢, 蚕儿
最佳答案
根据 [thread.thread.constr]§3,std::thread
构造函数的第一个参数的类型是 F&&
,要求 F
是 MoveConstructible
。在您的例子中,F
是 Thread
,它不是 MoveConstructible
。
换句话说,std::thread
需要按值存储仿函数,而您将仿函数作为抽象的 Thread
转发。
关于具有可变函数参数的 C++ 多态性,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14996945/