c++ - 整数的数组比较

Question

这里我比较两个数组元素，如果数组元素相等SETPASSWORD=1;，否则SETPASSWORD=0; 但这里总是打印​​密码设置状态1即使数组不相等

#include <stdio.h>
#define ARY_SIZE 4
int password_set;
int main (void)
{
  //Local Declarations
  int numbersA[ARY_SIZE];
  int numbersB[ARY_SIZE];
  int i;
  int j;

  //Statements
  printf("Please Enter 10 Integers For Array A\n");
  for (int i = 0; i < ARY_SIZE; i++)
    scanf("%d", &numbersA[i]);

  printf("\nPlease Enter 10 Integers For Array B\n");
  for (int j = 0; j < ARY_SIZE; j++)
    scanf("%d", &numbersB[j]);

  for (int i = 0; i < ARY_SIZE; i++)
  {
    for (int j = 0; j < ARY_SIZE; j++)
    {
      if (numbersA[i] == numbersB[j])
        password_set=1;
      else
        password_set=0;
    }
  }
  printf(" password setstaus =%d",password_set);
  return 0;
}

Answer 1

你的逻辑是错误的。一旦一对数字不相等，您必须立即退出循环。

而且您也只需要一个循环:

password_set = 1 ;

for (int j = 0; j < ARY_SIZE; j++)
{
  if (numbersA[j] != numbersB[j])
  {
    password_set = 0;
    break ;
  }
}