我正在用 C++ 处理二维数组。我在连接数组和指针的概念时遇到困难。我知道它们在内存分配和访问元素方面是相关的。例如
int *arr;
int num = arr + 1*sizeof(int);
与
相同int arr[];
int num = arr[1];
我试图找到二维数组和指针之间相同的联系 这是我的代码
void printGrid(int **arr) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
cout << setw(3);
cout << arr[i][j] << " ";
}
cout << endl;
}
}
int main() {
int **grid;
srand(time(NULL));
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
grid[i][j] = rand() % 11;
}
}
printGrid(grid);
}
当我编译它时,它会编译。当我尝试运行它时,出现段错误。有人可以指出我的代码中的错误吗?
非常感谢
最佳答案
int **grid;
srand(time(NULL));
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
grid[i][j] = rand() % 11;
}
}
应该为动态数组分配内存的部分在哪里?也可能是因为它的元素?为了解决这个问题,你可以这样做
// Allocating memory for array and elements
int **grid = new int*[10];
for (int i = 0; i < 10; i++) {
grid[i] = new int[10];
}
// Now fill the array as you had in your code
//
...
// Deletion part
for (int i = 0; i < 10; i++) {
delete[] grid[i];
}
delete[] grid;
另外,
I'm working on 2D array in C++. I'm having trouble connecting the concepts of arrays and pointers. I know that they are related in terms of memory allocation and accessing elements. For example
int *arr; int num = arr + 1*sizeof(int);
is the same as
int arr[]; int num = arr[1];
不,它们不一样。但这是一样的:
int x[] = {0, 2, 3};
int *arr = x;
int num = *(arr + 1); //Look up pointer arithmetic; same as num=arr[1];
关于C++ - 使用指针表示法初始化二维数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36119514/