c++ 多态性——使用基指针访问派生函数

Question

有什么方法可以让我完成以下工作，或者有解决办法吗？我一定是遗漏了什么。

class base
{
public:
    int someInt;
    virtual void someFunction(){}
};

class derived : public base
{
public:
    void someFunction(){}
    void anotherFunction(){}
};

int main (int argc, char * const argv[]) {

    base* aBasePointer = new derived;

    aBasePointer->anotherFunction();

    delete aBasePointer

    return 0;
}

Answer 1

使用 dynamic_cast<> 向下转型指向派生类的指针(不要忘记测试结果)。

例如

if ((derived* p = dynamic_cast<derived*>(aBasePointer)))
{
  // p is of type derived.
  p->anotherFunction();
}