您好,我正在做一项类(class)作业,我遇到了收到的错误消息,它们是:
error 'strtoul' was not declared in this scope
error 'print' was not declared in this scope
error 'printf' was not declared in this scope
我输入的代码是:
using namespace std;
int main (int argc, const char * argv[]) {
unsigned long int a, tmp;
a = strtoul("01011111000110001001001011010011",ULL,2);
print(a);
//We always work on "a" pattern
print(tmp = a >> 4);
print(tmp = a << 6);
print(tmp = a & (long int) 0x3);
print(tmp = a & (char) 0x3);
print(tmp = a | (unsigned short) 0xf00f);
print(tmp = a ^ (long int) 0xf0f0f0f0);
return 0;
}
//Function prints unsigned long integer in hexadecimal and binary notation
void print(unsigned long b)
{
int i, no_bits = 8 * sizeof(unsigned long);
char binary[no_bits];
//Print hexadecimal notation
printf("Hex: %X\n", b);
//Set up all 32 bits with 0
for (i = 0; i < no_bits; i++) binary[i] = 0;
//Count and save binary value
for (i = 0; b != 0; i++) {
binary[i] = b % 2;
b = b/2;
}
//Print binary notation
printf("Bin: ");
for (i = 0 ; i < no_bits; i++) {
if ((i % 4 == 0) && (i > 0)) printf(" ");
printf("%d", binary[(no_bits - 1) - i]);
}
printf("\n\n");
}
但我不断收到错误信息:
error 'strtoul' was not declared in this scope
error 'print' was not declared in this scope
error 'printf' was not declared in this scope
无论我尝试什么,当我尝试声明它们时,我总是收到相同的错误消息,有什么帮助吗??
非常感谢,
本
最佳答案
您需要在程序顶部包含这些头文件:
#include <stdlib.h>
#include <stdio.h>
stdio库允许您进行输入/输出操作和 stdlib库定义了几个通用函数,包括将字符串转换为无符号长整数。
您需要将 print
方法移到 main
之前,您还应该将 ULL
更改为 NULL
你调用 strtoul
因为我认为那是一个错字。您可以在我提供的链接中查看文档。
关于c++ - 代码块问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20253847/