json - 如何在Django中将搜索查询结果转换为Json可序列化对象

Question

我在Django中运行过滤查询，返回结果如下。

 search_result = [{'code': '12345', 'city': 'city1', 'country': 'USA', 'state': 'state1'}, {'code': '15675', 'city': 'city2', 'country': 'USA', 'state': 'state2'}]

我将这个返回的数据存储到字典中。

data_dict["return_result"] = search_result
data_dict["is_success"] = True

现在我将这个 data_dict 作为 JsonResponse 返回。(因为这个 url 是使用 AJAX 调用的)。

JsonResponse(data_dict)

在这个过程中，我遇到了错误 -

[{'code': '12345', 'city': 'city1', 'country': 'USA', 'state': 'state1'}, {'code': '15675', 'city': 'city2', 'country': 'USA', 'state': 'state2'}] is not JSON serializable.

由于单引号，上述数据不是有效的 Json。如果所有单引号都替换为双引号，那么这是一个有效的 json。

有什么方法可以将其转换为有效的 json 或搜索查询返回有效的 json。

完整堆栈跟踪:

Traceback (most recent call last):
  File "/home/rana/DjangoProject/VirtualEnv/e/lib/python3.4/site-packages/django/core/handlers/base.py", line 149, in get_response
    response = self.process_exception_by_middleware(e, request)
  File "/home/rana/DjangoProject/VirtualEnv/e/lib/python3.4/site-packages/django/core/handlers/base.py", line 147, in get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
  File "/home/rana/DjangoProject/VirtualEnv/e/lib/python3.4/site-packages/django/contrib/auth/decorators.py", line 23, in _wrapped_view
    return view_func(request, *args, **kwargs)
  File "/home/rana/DjangoProject/Sanstha/sansthaonline/tenant/views/zip_city_search.py", line 37, in search_zip_city
    return JsonResponse(context)
  File "/home/rana/DjangoProject/VirtualEnv/e/lib/python3.4/site-packages/django/http/response.py", line 505, in __init__
    data = json.dumps(data, cls=encoder, **json_dumps_params)
  File "/usr/lib/python3.4/json/__init__.py", line 237, in dumps
    **kw).encode(obj)
  File "/usr/lib/python3.4/json/encoder.py", line 192, in encode
    chunks = self.iterencode(o, _one_shot=True)
  File "/usr/lib/python3.4/json/encoder.py", line 250, in iterencode
    return _iterencode(o, 0)
  File "/home/rana/DjangoProject/VirtualEnv/e/lib/python3.4/site-packages/django/core/serializers/json.py", line 115, in default
    return super(DjangoJSONEncoder, self).default(o)
  File "/usr/lib/python3.4/json/encoder.py", line 173, in default
    raise TypeError(repr(o) + " is not JSON serializable")
TypeError: [{'city': 'city1', 'country': 'USA', 'code': '12345', 'state': 'state1'}, {'city': 'city2', 'country': 'USA', 'code': '15675', 'state': 'state2'}] is not JSON serializable

Answer 1

这可能对您有帮助:-

import json
from django.shortcuts import HttpResponse
from django.core.serializers.json import DjangoJSONEncoder

search_result = [{'code': '12345', 'city': 'city1', 'country': 'USA', 'state': 'state1'}, {'code': '15675', 'city': 'city2', 'country': 'USA', 'state': 'state2'}]


data = {'is_success':True,'msg':'Yor Success message','return_result':list(search_result)}

return HttpResponse(json.dumps(data,cls=DjangoJSONEncoder),content_type="application/json")