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我有一个问题，不知道如何解决。 我需要从选择中获取特定对象，例如 { “iso”:“UA”， “故事”:122， “标题”:乌克兰
所以我有一个sql查询
SELECT
c.iso,
locale.title as title,
(SELECT COUNT(DISTINCT s.id) FROM stories AS s WHERE s.country_id = c.id) AS stories
FROM `countries` AS c
LEFT JOIN countries_locale AS c_l ON c.id=c_l.country_id
LEFT JOIN locales AS locale ON c_l.locale_id=locale.id
WHERE locale.locale = 'en'
GROUP BY c.id
HAVING stories>0
它工作正常，所以我尝试将此查询重写为 Laravel QB:
DB::table($this->getTable())
->select(
'countries.iso as iso',
'locales.title as title',
DB::raw('(SELECT COUNT(s.id) FROM stories AS s WHERE s.country_id = countries.id) AS stories')
)
->leftJoin('countries_locale', 'countries.id', '=', 'countries_locale.country_id')
->leftJoin('locales', 'countries_locale.locale_id', '=', 'locales.id')
->where('locales.locale', \App::getLocale())
->groupBy('iso')
->having('stories', '>', 0)
->get();
然后我得到一个错误
Syntax error or access violation: 1055 'way.countries.id' isn't in GROUP BY
并向我展示了一个 sql 字符串，我可以在 mysql 中成功执行它