我正在构建一个数据库来存储公司的客户数据。数据库中的表已规范化，因此我有多个使用外键约束链接在一起的表。
Microsoft Access 将用于与数据库交互(作为前端)。为了使事情更简单，我创建了一个 View ，将所有必需的表连接在一起，以便最终用户可以轻松查询信息。
我遇到的问题涉及将信息插入此 View 。据我了解，由于我的 View 中有多个表，因此我必须使用带有 INSTEAD OF INSERT 语句的触发器。我已经创建了触发器；但是，我不确定如何使用表中的 ID 列(它们充当键)。
我有一个 MemberBasicInformation 表，其中包含客户的出生日期、姓名、性别等及其 MemberID。此 ID 是表中的一个 IDENTITY 列，因此它是自动生成的。我遇到的问题是，因为标识是自动生成的，所以我无法获取插入到 MemberBasicInformation 表后生成的标识值并将其插入到其他相关表。当我尝试这样做时，我最终会违反外键约束。
我试过使用 @@Identity 和 Scope_Identity() 无济于事。我列出了我的观点和触发器，让您了解事情是如何设置的。如果有人能指出我正确的方向，我将不胜感激。我真的很茫然。
成员 View :
CREATE VIEW [dbo].[Member]
AS
SELECT
dbo.MemberBasic.MemberId, dbo.MemberBasic.FirstName,
dbo.MemberBasic.MiddleInitial, dbo.MemberBasic.LastName,
dbo.MemberBasic.FullName, dbo.MemberBasic.DateOfBirth,
dbo.Gender.Name AS Gender, dbo.MemberBasic.Address,
dbo.MemberBasic.Address2, dbo.MemberBasic.City,
dbo.MemberBasic.State, dbo.MemberBasic.ZipCode,
dbo.MemberBasic.PhoneNumber,
dbo.MemberBasic.SocialSecurityNumber,
dbo.MemberBasic.DriversLicense,
dbo.MemberBasic.EmployerIdentificationNumber,
dbo.MemberBasic.Notes,
dbo.FieldRep.Name AS FieldRepName,
dbo.MemberDetail.DateAssigned AS FieldRepDateAssigned,
dbo.MemberDetail.CPReceivedOn, dbo.MemberDetail.CredentialedOn,
dbo.MemberEligibility.IsActive, dbo.ICO.Name AS ICO,
dbo.MemberEligibility.StartDate AS EligibilityStartDate,
dbo.MemberEligibility.EndDate AS EligibilityEndDate,
dbo.MemberWorkerCompDetail.ExpirationDate AS WorkerCompExpirationDate,
dbo.MemberWorkerCompDetail.AuditDate AS WorkerCompAuditDate,
dbo.WorkerCompTier.Name AS WorkerCompTier,
dbo.MemberAttachment.AttachmentId,
dbo.MemberAttachment.Data AS AttachmentData
FROM
dbo.MemberAttachment
INNER JOIN
dbo.MemberBasic ON dbo.MemberAttachment.MemberId = dbo.MemberBasic.MemberId
INNER JOIN
dbo.MemberCaregiverAssignment ON dbo.MemberAttachment.MemberId = dbo.MemberCaregiverAssignment.MemberId
INNER JOIN
dbo.MemberDetail ON dbo.MemberBasic.MemberId = dbo.MemberDetail.MemberId
INNER JOIN
dbo.MemberEligibility ON dbo.MemberAttachment.MemberId = dbo.MemberEligibility.MemberId
INNER JOIN
dbo.MemberWorkerCompDetail ON dbo.MemberAttachment.MemberId = dbo.MemberWorkerCompDetail.MemberId
INNER JOIN
dbo.Gender ON dbo.MemberBasic.GenderId = dbo.Gender.GenderId
INNER JOIN
dbo.FieldRep ON dbo.MemberDetail.FieldRepId = dbo.FieldRep.FieldRepId
INNER JOIN
dbo.ICO ON dbo.MemberEligibility.ICOId = dbo.ICO.ICOId
INNER JOIN
dbo.WorkerCompTier ON dbo.MemberWorkerCompDetail.TierId = dbo.WorkerCompTier.TierId
GO
MEMBER 触发器:
ALTER TRIGGER [dbo].[InsertNewMember]
ON [dbo].[Member]
INSTEAD OF INSERT
AS
BEGIN
SET NOCOUNT ON;
INSERT INTO MemberBasic (FirstName, MiddleInitial, LastName, GenderId, DateOfBirth, Address, Address2, City, State, ZipCode, PhoneNumber, SocialSecurityNumber, DriversLicense, EmployerIdentificationNumber, Notes)
SELECT
FirstName, MiddleInitial, LastName, GenderId, DateOfBirth,
Address, Address2, City, State, ZipCode, PhoneNumber,
SocialSecurityNumber, DriversLicense,
EmployerIdentificationNumber, Notes
FROM
inserted
INNER JOIN
Gender ON Gender.Name = Gender;
INSERT INTO MemberDetail (MemberId, FieldRepId, DateAssigned, CPReceivedOn, CredentialedOn)
SELECT
MemberId, FieldRep.FieldRepId, FieldRepDateAssigned,
CPReceivedOn, CredentialedOn
FROM
inserted
INNER JOIN
FieldRep ON FieldRep.Name = FieldRepName;
INSERT INTO MemberEligibility (MemberId, ICOId, StartDate, EndDate)
SELECT
MemberId, ICOId, EligibilityStartDate, EligibilityEndDate
FROM
inserted
INNER JOIN
ICO ON ICO.Name = ICO;
INSERT INTO MemberWorkerCompDetail (MemberId, AuditDate, ExpirationDate, TierId)
SELECT
MemberId, WorkerCompAuditDate, WorkerCompExpirationDate, TierId
FROM
inserted
INNER JOIN
WorkerCompTier ON WorkerCompTier.Name = WorkerCompTier;
INSERT INTO MemberAttachment (MemberId, Data)
SELECT MemberId, AttachmentData
FROM Member
END
最佳答案
您可以通过使用表变量来保存新插入的 ID 和您要插入到其他表中的所有数据来做到这一点。您需要这样做，因为没有办法从第一个 INSERT 的数据返回到 inserted，这样您就可以匹配 IDENTITY 值以及导致它们生成的行。
我们还必须滥用 MERGE，因为 INSERT 不允许您在其 OUTPUT 子句中包含目标表以外的任何内容。
我在玩具示例中这样做，但希望您能了解如何为您的完整表结构编写它。
首先是一些表格:
create table dbo.Core (
ID int IDENTITY(-71,3) not null,
A varchar(10) not null,
constraint PK_Core PRIMARY KEY (ID)
)
go
create table dbo.Child1 (
ID int IDENTITY(-42,19) not null,
ParentID int not null,
B varchar(10) not null,
constraint PK_Child1 PRIMARY KEY (ID),
constraint FK_Child1_Core FOREIGN KEY (ParentID) references Core(ID)
)
go
create table dbo.Child2 (
ID int IDENTITY(-42,19) not null,
ParentID int not null,
C varchar(10) not null,
constraint PK_Child2 PRIMARY KEY (ID),
constraint FK_Child2_Core FOREIGN KEY (ParentID) references Core(ID)
)
go
和 View :
create view dbo.Together
with schemabinding
as
select
c.ID,
c.A,
c1.B,
c2.C
from
dbo.Core c
inner join
dbo.Child1 c1
on
c.ID = c1.ParentID
inner join
dbo.Child2 c2
on
c.ID = c2.ParentID
go
最后是触发器:
create trigger Together_T_I
on dbo.Together
instead of insert
as
set nocount on
declare @tmp table (ID int not null, B varchar(10) not null, C varchar(10) not null);
merge into dbo.Core c
using inserted i
on
c.ID = i.ID
when not matched then insert (A) values (i.A)
output
inserted.ID /* NB - This is the output clauses inserted,
not the trigger's inserted so this is now populated */
,i.B,
i.C
into @tmp;
insert into dbo.Child1(ParentID,B)
select ID,B
from @tmp
insert into dbo.Child2(ParentID,C)
select ID,C
from @tmp
(我会在其中保留类似注释的内容，因为包含 OUTPUT 子句的触发器中的语句往往非常困惑，因为有两个 插入 游戏中的表格)
(还值得注意的是，在 MERGE 的 ON 子句中放入什么并不重要，只要您确定它将 < em>fail 来匹配。你可能更喜欢，比方说，只是 1=0 如果你认为这样更清楚。我只是因为触发器的 inserted.ID 将为 NULL)
现在我们开始插入:
insert into dbo.Together(A,B,C) values ('aaa','bbb','ccc')
go
select * from dbo.Together
并得到结果:
ID A B C
----------- ---------- ---------- ----------
-71 aaa bbb ccc
关于sql - INSTEAD OF INSERT 触发器和标识列使用 View ，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/43060392/