我觉得我的谷歌搜索技能现在很差,找不到 glibc 中的列表实现,找到了 hash和 tree实现,但不是列表。
是否有任何 glibc 实现?我不想重新格式化 linux kernel linked list宏并在用户空间中使用它们。
最佳答案
/usr/include/sys/queue.h
包含各种链表变体。(超过 man page 文档)
这是一个 TAIL_QUEUE 的例子: 通过预处理器 (gcc -E -c prog.c) 运行它以更容易地查看它是如何运行的 在引擎盖下工作)
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <sys/queue.h>
struct Block {
char text[64];
//linked list entry
TAILQ_ENTRY(Block) blocks;
};
struct File {
char name[128];
//list of blocks in the "file"
TAILQ_HEAD(,Block) head;
};
void add_block(struct File *f, const char *txt)
{
struct Block *b = malloc(sizeof *b);
strcpy(b->text,txt);
TAILQ_INSERT_TAIL(&f->head, b, blocks);
}
void print_file(struct File *f)
{
struct Block *b;
printf("File: %s\n", f->name);
TAILQ_FOREACH(b, &f->head, blocks) {
printf("Block: %s\n", b->text);
}
}
void delete_block(struct File *f, const char *txt)
{
struct Block *b, *next;
for(b = TAILQ_FIRST(&f->head) ; b != NULL ; b = next) {
next = TAILQ_NEXT(b, blocks);
if(strcmp(b->text, txt) == 0) {
TAILQ_REMOVE(&f->head, b, blocks);
free(b);
}
}
}
void delete_all_blocks(struct File *f)
{
struct Block *b;
while((b = TAILQ_FIRST(&f->head))) {
TAILQ_REMOVE(&f->head, b, blocks);
free(b);
}
}
int main(void)
{
struct File f;
TAILQ_INIT(&f.head);
strcpy(f.name,"Test.f");
add_block(&f,"one");
add_block(&f,"two");
add_block(&f,"three");
print_file(&f);
puts("\nDeleting three");
delete_block(&f, "three");
print_file(&f);
puts("\nAdding 2 blocks");
add_block(&f,"three");
add_block(&f,"three");
print_file(&f);
puts("\nDeleting three");
delete_block(&f, "three");
print_file(&f);
delete_all_blocks(&f);
return 0;
}
关于c - glibc - 列表和其他数据结构实现,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16819910/