sql - 尝试查找不同的数据时返回相同的结果

Question

我可以从下面的查询中获取每年的 15/02 - 21/06 日期范围数据。

SELECT * FROM dim_date
WHERE EXTRACT (MONTH FROM date_cal) BETWEEN 3 AND 5
 OR (EXTRACT (MONTH FROM date_cal) = 2 AND EXTRACT (DAY FROM date_cal) >= 15)
 OR (EXTRACT (MONTH FROM date_cal) = 6 AND EXTRACT (DAY FROM date_cal) <= 21)

但问题是，当我想查找 2010 - 2012 年份时，我得到了相同的结果。

我想得到的范围:

2010-02-15 - 2010-06-15
2011-02-15 - 2011-06-15
2012-02-15 - 2012-06-15

SELECT * FROM dim_date
WHERE EXTRACT (MONTH FROM date_cal) BETWEEN 3 AND 5
 OR (EXTRACT (MONTH FROM date_cal) = 2 AND EXTRACT (DAY FROM date_cal) >= 15)
 OR (EXTRACT (MONTH FROM date_cal) = 6 AND EXTRACT (DAY FROM date_cal) <= 21)
AND EXTRACT (YEAR FROM date_cal) BETWEEN 2010 AND 2012

谁能帮帮我!

Answer 1

您的问题是缺少括号:在 SQL 中，AND 优先于 OR，因此您需要将整个前面的表达式括起来:

SELECT * FROM dim_date
WHERE ( -- added bracket
 EXTRACT (MONTH FROM date_cal) BETWEEN 3 AND 5
 OR (EXTRACT (MONTH FROM date_cal) = 2 AND EXTRACT (DAY FROM date_cal) >= 15)
 OR (EXTRACT (MONTH FROM date_cal) = 6 AND EXTRACT (DAY FROM date_cal) <= 21)
 ) -- added bracket
AND EXTRACT (YEAR FROM date_cal) BETWEEN 2010 AND 2012

没有括号，你得到 A or B or (C and D)，但你想要 (A or B or C) and D