php - php中的mysql错误

Question

我正在尝试运行此 php 代码，该代码应显示来自 mysql 的引用，但无法弄清楚哪里出错了。结果变量为 null 或空。有人可以帮我吗。谢谢!

<?php
include 'config.php';

// 'text' is the name of your table that contains
// the information you want to pull from
$rowcount = mysql_query("select count(*) as rows from quotes");

// Gets the total number of items pulled from database.
while ($row = mysql_fetch_assoc($rowcount))
{
$max = $row["rows"];
//print_r ($max);
}

// Selects an item's index at random 
$rand = rand(1,$max)-1;
print_r ($rand);
$result = mysql_query("select * from quotes limit $rand, 1") or die ('Error: '.mysql_error());
if (!$result or mysql_num_rows($result))
{
echo "Empty";
}
else{
while ($row = mysql_fetch_array($result)) {

$randomOutput = $row['cQuotes'];
echo '<p>' . $randomOutput . '</p>';
}
}

Answer 1

$result = mysql_query("SELECT * FROM quotes ORDER BY rand() LIMIT 1") or die ('Error: '.mysql_error());
if (!$result || mysql_num_rows($result) == 0)
    echo "Empty";
else {
    while ($row = mysql_fetch_array($result)) {
        $randomOutput = $row['cQuotes'];
        echo '<p>' . $randomOutput . '</p>';
    }
}