mysql - 从每个领域获得总值(value)？

Question

如何获取每个用户名的是、否、其他字段的总值？

我喜欢添加 Total 字段。

SELECT Username,
  SUM(CASE WHEN type = 'Yes' THEN 1 ELSE NULL END) as Yes,
  SUM(CASE WHEN type = 'No' THEN 1 ELSE NULL END) as No,
  SUM(CASE WHEN type = '' THEN 1 ELSE NULL END) as Other  
  //How to get total of Yes/No/Other
  FROM table 
WHERE source = 'CompanyName' ";

最高的总计也排在最前面。

Answer 1

使用 0 代替 NULL，添加缺少的 group by 并使用 COUNT(*) 获取每个组和顺序的总数结果:

SELECT Username,
  SUM(CASE WHEN type = 'Yes' THEN 1 ELSE 0 END) as Yes,
  SUM(CASE WHEN type = 'No' THEN 1 ELSE 0 END) as No,
  SUM(CASE WHEN type = '' THEN 1 ELSE 0 END) as Other,  
  COUNT(*) as TOTAL
  FROM table 
WHERE source = 'CompanyName'
group by Username
order by TOTAL desc;

这假定 type 只能是"is"、“否”或“”。