我有以下查询:
-- Compare current period to historical data
select Name ,
avg(TimeProcessing + TimeRendering + TimeDataRetrieval) / 1000 as 'Current Month' ,
isnull(count(TimeProcessing), 0) as 'Sample' ,
min(l2.[Avg_Exec_Time_Previous_Month]) as 'Previous Month' ,
isnull(min(l2.[Executions_Last_Month]), 0) as 'Sample' ,
min(l3.[Avg_Exec_Time_Two_Months_Ago]) as 'Two Months ago' ,
isnull(min(l3.[Executions_Two_Months_Ago]), 0) as 'Sample'
from marlin.report_execution_log l
inner join marlin.report_catalog c on l.ReportID = c.ItemID
left outer join (
select
l2.ReportID ,
(
avg(l2.TimeProcessing + l2.TimeRendering
+ l2.TimeDataRetrieval) / 1000
) as 'Avg_Exec_Time_Previous_Month' ,
count(l2.TimeProcessing) as 'Executions_Last_Month'
from
marlin.report_execution_log l2
where
TimeEnd between dateadd(MONTH, -2, getdate())
and dateadd(MONTH, -1, getdate())
group by
l2.ReportID
) l2 on l.ReportID = l2.ReportID
left outer join (
select
l3.ReportID ,
(
avg(l3.TimeProcessing + l3.TimeRendering + l3.TimeDataRetrieval) / 1000
) as 'Avg_Exec_Time_Two_Months_Ago' ,
count(l3.TimeProcessing) as 'Executions_Two_Months_Ago'
from
marlin.report_execution_log l3
where
TimeEnd between dateadd(MONTH, -3, getdate())
and dateadd(MONTH, -2, getdate())
group by
l3.ReportID
) l3 on l.ReportID = l3.ReportID
group by l.ReportID ,
Name
order by 2 desc
这带来了以下结果:
不幸的是,我们的一份报告在整个月内更改了名称,随后我需要合并这两行。这可能吗?如何合并两行?例如,如何使用第一行报告名称让第一行和第二行显示附加结果?
最佳答案
如果我理解得很好,你只需要在你的选择和你的组中有一个案例陈述......就像
select case when Name = 'Project1' then 'Project1'
when Name = 'Project2' then 'Project1'
else Name
end as NAME
.......
group by case when Name = 'Project1' then 'Project1'
when Name = 'Project2' then 'Project1'
else Name
end
如果你的case是现在是Project 1,一个月前是Project 2,你可能需要在case statement中加上日期(以防万一)
select case when Name = 'Project1' and TimeEnd = getdate() then 'Project1'
when Name = 'Project2' and TimeEnd = dateadd(MONTH, -1, getdate()) then 'Project1'
else Name
end as NAME
.......
group by case when Name = 'Project1' and TimeEnd = getdate() then 'Project1'
when Name = 'Project2' and TimeEnd = dateadd(MONTH, -1, getdate()) then 'Project1'
else Name
end
就是这个想法。
编辑。
我认为如果他们重复出现,您可以选择,但我一点都不喜欢
SELECT NAME, AVG(Current Month) as Current Month, count(Sample) as Sample, min(Previous Month) as Previous Month, min(Sample2) as Sample2, min(Two Months ago) as Two Months ago,
min(Sample3) as Sample3
FROM
(
select Name ,
avg(TimeProcessing + TimeRendering + TimeDataRetrieval) / 1000 as 'Current Month' ,
isnull(count(TimeProcessing), 0) as 'Sample' ,
min(l2.[Avg_Exec_Time_Previous_Month]) as 'Previous Month' ,
isnull(min(l2.[Executions_Last_Month]), 0) as 'Sample2' ,
min(l3.[Avg_Exec_Time_Two_Months_Ago]) as 'Two Months ago' ,
isnull(min(l3.[Executions_Two_Months_Ago]), 0) as 'Sample3'
from marlin.report_execution_log l
inner join marlin.report_catalog c on l.ReportID = c.ItemID
left outer join (
select
l2.ReportID ,
(
avg(l2.TimeProcessing + l2.TimeRendering
+ l2.TimeDataRetrieval) / 1000
) as 'Avg_Exec_Time_Previous_Month' ,
count(l2.TimeProcessing) as 'Executions_Last_Month'
from
marlin.report_execution_log l2
where
TimeEnd between dateadd(MONTH, -2, getdate())
and dateadd(MONTH, -1, getdate())
group by
l2.ReportID
) l2 on l.ReportID = l2.ReportID
left outer join (
select
l3.ReportID ,
(
avg(l3.TimeProcessing + l3.TimeRendering + l3.TimeDataRetrieval) / 1000
) as 'Avg_Exec_Time_Two_Months_Ago' ,
count(l3.TimeProcessing) as 'Executions_Two_Months_Ago'
from
marlin.report_execution_log l3
where
TimeEnd between dateadd(MONTH, -3, getdate())
and dateadd(MONTH, -2, getdate())
group by
l3.ReportID
) l3 on l.ReportID = l3.ReportID
group by l.ReportID ,
Name
)
group by Name
order by 2 desc
关于sql - 如何合并结果中的两行而不是所有结果?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8844474/