当我取出条件来加载数据时,它会将其保存到数据库中,$_POST 获取值但不会将它们发送到 Controller ,这种方式适用于我的其他项目但不适用于此处。如果我使用 if(isset($_POST['money']) && isset($_POST['username'])){
来保存数据它可以工作但不是 load()
函数。
Controller
public function actionSend() {
$model = new User();
$model->getErrors();
if ($model->load(Yii::$app->request->post())) {
$model->money = 'something';
$model->username = 'something';
$model->save();
}
return $this->render('send', [
'model' => $model
]);
}
模型
<?php
namespace app\models;
use yii\db\ActiveRecord;
use Yii;
class User extends \yii\db\ActiveRecord {
public static function tableName() {
return 'user';
}
public function rules() {
return [
[['username', 'money'], 'safe'],
[['username', 'password'], 'string', 'max' => 15],
[['auth_key', 'access_token'], 'string', 'max' => 32],
[['money'], 'string', 'max' => 8],
];
}
public function attributeLabels() {
return [
'id' => 'ID',
'username' => 'Username',
'password' => 'Password',
'auth_key' => 'Auth Key',
'access_token' => 'Access Token',
'money' => 'Money',
];
}
}
查看
<?php
use yii\helpers\Html;
use yii\bootstrap\ActiveForm;
?>
<h2>Send</h2>
<?php $form = ActiveForm::begin([
'layout' => 'horizontal',
'fieldConfig' => [
'template' => "{label}\n<div class=\"col-lg-3\">{input}</div>\n<div class=\"col-lg-8\">{error}</div>",
'labelOptions' => ['class' => 'col-lg-1 control-label'],
],
]); ?>
<?= $form->field($model, 'username')->textInput(['name' => 'username']) ?>
<?= $form->field($model, 'money')->textInput(['name' => 'money'])?>
<div class="form-group">
<div class="col-lg-offset-1 col-lg-11">
<?= Html::submitButton('Send', ['class' => 'btn btn-success']) ?>
</div>
</div>
<?php ActiveForm::end(); ?>
最佳答案
把你的 Controller 改成这个
public function actionSend() {
$model = new User();
$model->getErrors();
/* set the second parameters of load to empty string */
if ($model->load(Yii::$app->request->post(), '')) {
$model->money = 'something';
$model->username = 'something';
$model->save();
}
return $this->render('send', [
'model' => $model
]);
}
如果您查看 load 的执行情况方法,你会发现
load
有两个参数,第一个是你要赋值的数据,第二个是数据的前缀名。
让我们看一个例子来说明第二个参数的用法。 (我们假设您的表单名称是 User
)
$data1 = [
'username' => 'sam',
'money' => 100
];
$data2 = [
'User' => [
'username' => 'sam',
'money' => 100
],
],
// if you want to load $data1, you have to do like this
$model->load($data1, '');
// if you want to load $data2, you have to do like this
$model->load($data2);
// either one of the two ways, the result is the same.
echo $model->username; // sam
echo $model->money; // 100
希望对您有所帮助。
关于php - Yii2 $model->load(Yii::$app->request->post()) 不从表单加载数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47351260/