我正在开发一个网络应用程序 (PHP + MySQL),用户可以在其中通过输入一些搜索字符串来搜索其他用户。
我需要将用户的输入字符串与我的数据库中“用户”表的 2 列(用户名和全名)相匹配,并返回最相关(20 或 50)的匹配项。最理想的是,我还需要考虑拼写错误。
我该如何处理?我不想在这里重新发明轮子。
最佳答案
您可以使用 MySQL full Text search 来完成:
我想给你解释一下 Boolean Full Text Search ;但我建议你通过Full Text Search using Query Expansion还有。
让我们看一下 dev.mysql.com 上给出的示例表:
mysql> select * from articles;
+----+-----------------------+------------------------------------------+
| id | title | body |
+----+-----------------------+------------------------------------------+
| 1 | PostgreSQL Tutorial | DBMS stands for DataBase ... |
| 2 | How To Use MySQL Well | After you went through a ... |
| 3 | Optimizing MySQL | In this tutorial we will show ... |
| 4 | 1001 MySQL Tricks | 1. Never run mysqld as root. 2. ... |
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
| 6 | MySQL Security | When configured properly, MySQL ... |
+----+-----------------------+------------------------------------------+
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('"database comparison"' IN BOOLEAN MODE);
+----+-------------------+------------------------------------------+
| id | title | body |
+----+-------------------+------------------------------------------+
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
+----+-------------------+------------------------------------------+
当引用单词时,顺序很重要:
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('"comparison database"' IN BOOLEAN MODE);
Empty set (0.01 sec)
当我们删除引号时,它将搜索包含单词“数据库”或“比较”的行:
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('database comparison' IN BOOLEAN MODE);
+----+---------------------+------------------------------------------+
| id | title | body |
+----+---------------------+------------------------------------------+
| 1 | PostgreSQL Tutorial | DBMS stands for DataBase ... |
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
+----+---------------------+------------------------------------------+
现在顺序无关紧要:
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('comparison database' IN BOOLEAN MODE);
+----+---------------------+------------------------------------------+
| id | title | body |
+----+---------------------+------------------------------------------+
| 1 | PostgreSQL Tutorial | DBMS stands for DataBase ... |
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
+----+---------------------+------------------------------------------+
如果我们想要获取包含单词“PostgreSQL”或短语“数据库比较”的行,我们应该使用这个请求:
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('PostgreSQL "database comparison"' IN BOOLEAN MODE);
+----+---------------------+------------------------------------------+
| id | title | body |
+----+---------------------+------------------------------------------+
| 1 | PostgreSQL Tutorial | DBMS stands for DataBase ... |
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
+----+---------------------+------------------------------------------+
确保您要搜索的词不在 list of stopwords 中, 被忽略。
(很明显像'is','the'这样的词是stopwords,那些被忽略了)
要在 bool 模式下增强结果的排序,您可以使用以下查询:
(假设您在用户输入的字符串中总共有 2 个单词)那么。
SELECT column_names, MATCH (text) AGAINST ('word1 word2')
AS col1 FROM table1
WHERE MATCH (text) AGAINST ('+word1 +word2' in boolean mode)
order by col1 desc;
(如果用户输入字符串中有 3 个单词)那么..
SELECT column_names, MATCH (text) AGAINST ('word1 word2 word3')
AS col1 FROM table1
WHERE MATCH (text) AGAINST ('+word1 +word2 +word3' in boolean mode)
order by col1 desc;
使用first MATCH()
我们在非 bool 搜索模式下得到分数(更有特色)。 第二个 MATCH()
确保我们真正只返回我们想要的结果(包含所有 3 个单词)。
关于mysql - 为给定字符串搜索数据库的好算法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29467667/