php - 以 laravel 形式更新按钮点击的数据库

Question

我有这个想法

{{ Form::open() }}
@if($order->paid == 0)
    <button type="submit" class="btn btn-primary" value="1">Mark Order as Paid</a>
@else
    <button type="submit" class="btn btn-primary" value="0">Mark Order as Unpaid</a>
@endif
{{ Form::close() }}

这在我的 Controller 中

public function ordersPaidSubmit($orderId) {       
    $order = Order::where('order_id', $orderId)->first();
    if (!$order) {
        App::abort(404);
}

    $paid = Input::get('paid');
    $order->save();

    return Redirect::to('/admin/orders');
}

是否可以像这样为按钮 0 或 1 赋值，然后点击更新数据库列？目前不更新，但如何更新？

Answer 1

您可以像这样在每个按钮中放置一个隐藏字段:

{{ Form::open() }}
@if($order->paid == 0)
    {{ Form::hidden('paid', 1, ['id' => 'paid']) }}
    <button type="submit" class="btn btn-primary" value="1">Mark Order as Paid</a>
@else
    {{ Form::hidden('paid', 0, ['id' => 'paid']) }}
    <button type="submit" class="btn btn-primary" value="0">Mark Order as Unpaid</a>
@endif
{{ Form::close() }}

所以隐藏字段看起来像

<input id="paid" name="paid" type="hidden" value="1">
and
<input id="paid" name="paid" type="hidden" value="0">

我确定您想在 Controller 中使用 $order 而不是 $paid。所以改变这一行

$paid = Input::get('paid');

白色

$order->paid = Input::get('paid');

您的表单按钮将起作用。