我正在将一些字段插入到数据库中，这是我可以做到的。我采用了一个触发器，将数据插入表“AFTER INSERT”事件。
<html>
<body>
<?php
$id=$_POST['id'];
$a=$_POST['id'];
$fname=$_POST['fname'];
$lname=$_POST['lname'];
$city=$_POST['city'];
$con=mysqli_connect('127.0.0.1:3306' ,'root','root','my_db');
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql1="select * from table2";
$result = mysqli_query($con,$sql1);
echo "<table border='1'>
<tr>
<th>Id</th>
<th>Firstname</th>
<th>Lastname</th>
<th>City</th>
</tr>";
while($row = mysqli_fetch_array($result,MYSQLI_ASSOC))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['fname'] . "</td>";
echo "<td>" . $row['lname'] . "</td>";
echo "<td>" . $row['city'] . "</td>";
echo "</tr>";
}
echo "</table>";
$sql3 = "在每行的 temp2 上插入后创建触发器 MysqlTrigger 开始插入临时值(new.id,new.fname,new.lname,new.city,new.city);"; mysqli_query($con,$sql3);
$sql5="INSERT INTO temp2 (id,fname, lname, city)
VALUES
('$_POST[id]','$_POST[fname]','$_POST[lname]','$_POST[city]')";
mysqli_query($con,$sql5);
echo "1 record added";
//--------------- Trigger started ------------------
print "<h2>CREATE MySQL Trigger In PHP</h2>";
echo "<table border='1'>
<tr>
<th>Id</th>
<th>Firstname</th>
<th>Lastname</th>
<th>City</th>
<th>Status</th>
</tr>";
$sql4="select * from temp";
$res = mysqli_query($con,$sql4);
while($row = mysqli_fetch_array($res,MYSQLI_ASSOC))
{
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['fname'] . "</td>";
echo "<td>" . $row['lname'] . "</td>";
echo "<td>" . $row['city'] . "</td>";
echo "<td>" . $row['stat'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
</body>
</html>
这成功地将数据插入到 temp2 表中，但触发器中的事件不会对临时表进行任何更改。
我哪里出错了？
最佳答案
来自 mySQL manual
delimiter |
CREATE TRIGGER testref BEFORE INSERT ON test1
FOR EACH ROW BEGIN
INSERT INTO test2 SET a2 = NEW.a1;
DELETE FROM test3 WHERE a3 = NEW.a1;
UPDATE test4 SET b4 = b4 + 1 WHERE a4 = NEW.a1;
END;
|
delimiter ;
触发器上缺少分隔符和结束
您到底为什么要尝试使用 php 创建触发器？你不能在 MySQL Workbench 上使用 phpMyAdmin 创建它吗？触发器应该存在于数据库中...如果它不应该是永久的，您应该将其放在 php 代码的末尾...
关于mysql - 触发器确实对表进行了更改，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/17445045/