我想在 MySQL 中编写 bool 全文搜索查询。但我想按以下顺序得到结果:
完全匹配
> 包括所有单词
> 包括部分单词
(>
表示更高。)
通过以下查询,我得到了更高的精确匹配:
SELECT *, MATCH(name,description,address)
AGAINST('>("word1 word2 word3") <(word1 word2 word3)' IN BOOLEAN MODE)
AS score FROM samples WHERE MATCH(name,description,address)
AGAINST('>("word1 word2 word3") <(word1 word2 word3)' IN BOOLEAN MODE) ORDER BY score DESC
通过以下查询,我得到的文档包含的所有单词都高于包含查询某些部分的单词:
SELECT *, MATCH(name,description,address)
AGAINST('>(+word1 +word2 +word3) <(word1 word2 word3)' IN BOOLEAN MODE)
AS score FROM samples WHERE MATCH(name,description,address)
AGAINST('>(+word1 +word2 +word3) <(word1 word2 word3)' IN BOOLEAN MODE) ORDER BY score DESC
但我想合并这两个查询。这是迄今为止我得到的最好的结果,但我没有得到我想要的结果。
SELECT *, MATCH(name,description,address)
AGAINST('>("word1 word2 word3") <(>(+word1 +word2 +word3) <(word1 word2 word3))' IN BOOLEAN MODE)
AS score FROM samples WHERE MATCH(name,description,address)
AGAINST('>("word1 word2 word3") <(>(+word1 +word2 +word3) <(word1 word2 word3))' IN BOOLEAN MODE)
ORDER BY score DESC
有没有办法在没有 UNION 的情况下做到这一点?
最佳答案
这行得通吗?
SELECT *,
MATCH (name,description,address)
AGAINST ('"word1 word2 word3"' IN BOOLEAN MODE) score_exact,
MATCH (name,description,address)
AGAINST ('+word1 +word2 +word3' IN BOOLEAN MODE) score_all,
MATCH (name,description,address)
AGAINST ('word1 word2 word3' IN BOOLEAN MODE) score_some
FROM samples
WHERE MATCH (name,description,address)
AGAINST ('word1 word2 word3' IN BOOLEAN MODE)
ORDER BY score_exact DESC, score_all DESC, score_some DESC
关于MySQL 带有子表达式的 bool 全文搜索,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34534207/