PHP & 可湿性粉剂 : try catch not working when error from DB is thrown

Question

我目前正在尝试为以下情况编写错误处理。我希望能够在数据库为 --read-only 并尝试写入时捕获错误。

WordPress database error INSERT command denied to user 'readonly'@

抛出此错误是因为数据库是--read-only 并且正在尝试写入数据库。但是，这个错误应该已经被我的catch 条件捕获了。

function drools_request($data, $uid) {
  try {
    $db = _get_db();
    $db->insert("requests", [
      "uid" => $uid,
      "data" => json_encode($data),
    ]);
  }
  catch(Error $e){
    echo 'Error writing to database: ',  $e->getMessage(), "\n";
  }
}

正如您从上面的代码片段中看到的那样，$db->insert( 方法正确地中断了，因为它试图写入 $db 实例，即 - -只读。但是，catch(Error $e) 没有工作，为什么？

这是完整的类(class):

    <?php

namespace StatCollector;

function drools_request($data, $uid) {
  try {
    $db = _get_db();
    $db->insert("requests", [
      "uid" => $uid,
      "data" => json_encode($data),
    ]);
  }
  catch(Exception $e)
  {
    echo 'Error writing to database: ',  $e->getMessage(), "\n";
  }
}

function drools_response($response, $uid) {
  try {
    $db = _get_db();
    $db->insert("responses", [
      "uid" => $uid,
      "data" => json_encode($response),
    ]);
  }
  catch(Exception $e)
  {
    echo 'Error writing to database: ',  $e->getMessage(), "\n";
  }
}

function results_sent($type, $to, $uid, $url = null, $message = null) {
  try {
    $db = _get_db();
    $db->insert("messages", [
      "uid" => $uid,
      "msg_type" => strtolower($type),
      "address" => $to,
      "url" => $url,
      "message" => $message
    ]);
  }
  catch(Exception $e)
  {
    echo 'Error writing to database: ',  $e->getMessage(), "\n";
  }
}

function peu_data($staff, $client, $uid) {
  try {
    if (empty($uid)) {
      return;
    }
    $db = _get_db();

    if (! empty($staff)) {
      $db->insert("peu_staff", [
        "uid" => $uid,
        "data" => json_encode($staff)
      ]);
    }
    if (! empty($client)) {
      $db->insert("peu_client", [
        "uid" => $uid,
        "data" => json_encode($client)
      ]);
    }
  }
  catch(Exception $e)
  {
    echo 'Error writing to databse: ', $e->getMessage(), "\n";
  }
}

function response_update() {
  $uid = $_POST['GUID'];
  $url = $_POST['url'];
  $programs = $_POST['programs'];
  if (empty($uid) || empty($url) || empty($programs)) {
    wp_send_json(["status" => "fail","message" => "missing values"]);
    return wp_die();
  }

  try {
    $db = _get_db();
    $db->insert("response_update", [
      "uid" => $uid,
      "url" => $url,
      "program_codes" => $programs
    ]);
    wp_send_json(["status" => "ok"]);
    wp_die();
  }
  catch(Exception $e)
  {
    echo 'Error writing to database: ', $e->getMessage(), "\n";
  }
}

为什么 try 和 catch 不起作用？我能做些什么来解决这个问题？这篇文章没有用。 PHP try/catch and fatal error

Answer 1

您的代码位于自定义命名空间中:

namespace StatCollector;

所以这段代码:

catch (Exception $ex)

正在寻找 \StatCollector\Exception 的异常类，这不是抛出的:\Exception 是。

由于 Error 和 Exception 类位于 root 命名空间中，您需要执行以下操作:

catch (\Exception $ex)

和/或:

catch (\Error $ex)

或者只是:

catch (\Throwable $t)

然后也关注Bill Karwin's以上建议。