我确信之前已经有人问过这个问题并回答过,但要么我很愚蠢,要么没有一个答案对我有用。也许我只是不明白。然而,问题就在这里;我得到了这门课:
import sqlite3
class User:
def __init__(self, name, age):
self.name = name
self.age = age
def saveToDatabase(self):
connection = sqlite3.connect("users.db")
cur = connection.cursor()
cur.execute("DROP TABLE IF EXISTS users")
cur.execute("CREATE TABLE users (name TEXT PRIMARY KEY, age INTEGER)")
cur.execute("INSERT OR REPLACE INTO users VALUES (?,?)", (self.name, self.age))
connection.commit()
connection.close()
@staticmethod
def printUserFromDatabase(name):
connection = sqlite3.connect("users.db")
cur = connection.cursor()
cur.execute("SELECT * FROM users WHERE name=?", name)
print(cur.fetchone())
connection.close()
它可以工作,创建数据库,我可以向其中添加用户,但是当我尝试从数据库打印用户时,会发生这种情况:
>>> tom = User("Tom", 24)
>>> tom.saveToDatabase()
>>> User.printUserFromDatabase("Tom")
Traceback (most recent call last):
File "<pyshell#7>", line 1, in <module>
User.printUserFromDatabase("Tom")
File "C:\Users\Markus\Desktop\foo\foo.py", line 25, in printUserFromDatabase
cur.execute("SELECT * FROM users WHERE name=?", name)
sqlite3.ProgrammingError: Incorrect number of bindings supplied. The current statement uses 1, and there are 3 supplied.
>>>
最佳答案
由于 name 是可迭代的,它会尝试解压它...将其放入一个元组中,仅用其本身来修复
cur.execute("SELECT * FROM users WHERE name=?", (name,))
关于关于提供的绑定(bind)数量的 Python sqlite3 错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12626706/